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Yeah, if you know about entropy, you'll understand the next bit

ΔG = ΔH - TΔS is the Gibb's equation for energy 'lost'

The enthalpy change for water to ice is ΔH = -6.01kJmol-1, and ΔS = -22J K-1mol-1, and T = 273 K (as we are at 0oC), so subbing those in gives..

ΔG = -6.01 - 273 x -0.022

= 1/250

Therefore, as that value is very small, H2O(l) <---> H2O(s) at 0oC

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