yes
The cars have the same speed but different velocities because they are moving in different directions. To determine the overall velocity (magnitude and direction), you can use vector addition to find the resultant velocity.
The displacement of a particle is the change in its position from its initial point to its final point, taking into account direction. It can be calculated as the difference between the final position and the initial position vector of the particle.
The average velocity of a particle when it returns to the starting point is zero. This is because velocity is a vector quantity that includes both magnitude and direction, and returning to the starting point means the displacement is zero, resulting in an average velocity of zero.
Yes, it is possible to have zero displacement and a non-zero average velocity. This can occur if an object moves back and forth over a certain distance so that the total displacement is zero, but the average velocity is non-zero due to the object covering distance in both directions.
If displacement is not changing as a function of time, then velocity is zero. Velocity is the rate of change of displacement with respect to time, so if there is no change in displacement, the velocity is zero.
The cars have the same speed but different velocities because they are moving in different directions. To determine the overall velocity (magnitude and direction), you can use vector addition to find the resultant velocity.
To find average velocity, you need to know the displacement. If you knew displacement, average velocity would be found by: V = Displacement / time
The displacement of a particle is the change in its position from its initial point to its final point, taking into account direction. It can be calculated as the difference between the final position and the initial position vector of the particle.
The average velocity of a particle when it returns to the starting point is zero. This is because velocity is a vector quantity that includes both magnitude and direction, and returning to the starting point means the displacement is zero, resulting in an average velocity of zero.
There is not only "one" amplitude. There is an amplitude of particle displacement ξ, or displacement amplitude, an amplitude of sound pressure p or pressure amplitude, an amplitude of sound particle velocity v, or particle velocity amplitude, an amplitude of pressure gradient Δ p, or pressure gradient amplitude. If the "sound" inceases, the "amplitude" also increases.
The maximum displacement upwards is given by the equation y=-vxv/2g. At the peak, the value of velocity is said to be v=0.
If a be the amplitude of a particle executing SHM with an angular velocity w and yis the displacement, then velocity of the particle at any instant is given by u(t)=w J(a 2 y 2
Velocity is displacement divided by time. Displacement is different from distance traveled, as displacement states how far you traveled in RELATION to a starting point. The formula for Velocity is ---- v = x / t v = Velocity x = Displacement t = Time velocity is a vector quantity so the direction should also be specified unless it is implicit in the problem. ----
Yes, it is possible to have zero displacement and a non-zero average velocity. This can occur if an object moves back and forth over a certain distance so that the total displacement is zero, but the average velocity is non-zero due to the object covering distance in both directions.
If displacement is not changing as a function of time, then velocity is zero. Velocity is the rate of change of displacement with respect to time, so if there is no change in displacement, the velocity is zero.
Yes, velocity is the derivative of displacement.
Displacement is the change in position of an object, velocity is the rate of change of displacement, and acceleration is the rate of change of velocity. In the context of motion, displacement, velocity, and acceleration are related in that acceleration affects velocity, which in turn affects displacement.