No, the displacement can never be greater than the distance traveled. Displacement is a vector representing the straight-line distance between the start and end points, while the distance traveled is the actual length of the path taken. Since displacement is a straight-line measure, it can never exceed the distance traveled along a path with turns and curves.
Well, honey, displacement can definitely be greater than the total distance traveled by a moving object if that object has been doing some crazy zigzagging. Displacement is just the straight-line distance between the starting and ending points, while total distance is the actual path taken. So, if that object has been taking some detours and scenic routes, displacement can definitely end up being greater.
Sure. If the motion is all in a straight line, then the distance and displacement are equal. ==> The Olympic 100-meter sprint is in a straight line. Distance = Displacement = 100 meters. If the direction of motion ever changes, then the distance and displacement are not equal. (I think if the direction of motion ever changes, then the distance has to be greater than the displacement.) ==> In the Indianapolis 500, Distance = 500 miles, Displacement = Zero, because the Starting line and Finish line are in the same place, so the car finishes at the same place he started at.
The distance traveled is 135m (100m forward + 35m backward). The displacement is 65m forward (100m - 35m), as displacement is the difference between the final and initial positions regardless of the path taken.
Yes, the distance traveled up an inclined plane is called the "vertical distance" or "height," while the distance traveled along the incline is known as the "inclined distance" or "slope length." These distances can be calculated using trigonometry and the angle of inclination of the plane.
No, the distance covered by a moving object cannot be less than zero. Distance is always measured as a positive value. If an object is moving, it will always cover a distance greater than or equal to zero.
Well, honey, displacement can definitely be greater than the total distance traveled by a moving object if that object has been doing some crazy zigzagging. Displacement is just the straight-line distance between the starting and ending points, while total distance is the actual path taken. So, if that object has been taking some detours and scenic routes, displacement can definitely end up being greater.
No.
Sure. If the motion is all in a straight line, then the distance and displacement are equal. ==> The Olympic 100-meter sprint is in a straight line. Distance = Displacement = 100 meters. If the direction of motion ever changes, then the distance and displacement are not equal. (I think if the direction of motion ever changes, then the distance has to be greater than the displacement.) ==> In the Indianapolis 500, Distance = 500 miles, Displacement = Zero, because the Starting line and Finish line are in the same place, so the car finishes at the same place he started at.
The distance traveled is 135m (100m forward + 35m backward). The displacement is 65m forward (100m - 35m), as displacement is the difference between the final and initial positions regardless of the path taken.
what is the furthest distance a dog has ever traveld
No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A. Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A. An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.)
Yes, the distance traveled up an inclined plane is called the "vertical distance" or "height," while the distance traveled along the incline is known as the "inclined distance" or "slope length." These distances can be calculated using trigonometry and the angle of inclination of the plane.
Yes, have you ever traveled on the Mexican train system?
Acceleration= Distance/time (distance divided by time) That's the dumbest answer I've ever heard.. Acceleration = Final Velocity - Initial Velocity/Time Velocity = Displacement/Time So you can't calculate acceleration from distance and time, you can only do velocity.
no Kesha never traveled to Saudi Arabia.
No.
no but it would b nice