Consider a ball that picks up a speed of 2ms each second when it rolles from rest down and inclined plane if the ball takes 5 seconds to reach the bottom its speed at the bottom will be?

Answer 1

To do this question, we can take either an algebraic approach or a calculus approach. We can just imagine that over the course of 5 seconds, the ball will be rolling 10 meters per second. Simple 2 times 5. However, we could do this with calculus, though it isn't nessasary. f(t) = 2 This is the acceleration fucnction, and it means that it will always accelerate at a rate of 2 meters per second. Integrate with respect to time, t F(t) = 2t+C We can treat C as zero here, because the starting velocity is zero. Then we plug in five seconds to get 10 meters per second. Hope this helps!

Answer 2

The ball's speed at the bottom of the inclined plane can be calculated using the formula: final speed = initial speed + (acceleration * time). In this case, the initial speed is 0 m/s (ball starts from rest), acceleration is 2 m/s^2, and time is 5 seconds. So, the final speed of the ball at the bottom of the inclined plane would be 10 m/s.