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Q: Derive the expression for electric potential as line integral dueto charge distribution and due to adipole?
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What is potential difference of a monopole?

The simple answer: the potential at a point some distance, r from a monopole is kQ / r, where k is Coulumb's constant: 9.0E9 Q is the charge of the monopole and r is the distance from the monopole. And how to get there: Since electric force is kq1q2/ r2, the electric field ( Force per charge) is kQ/r2. The voltage of a particle is defined to be the integral of the electric field with respects to r. Thus integrating you get the above equation.


What is quntam numbers?

Quantum numbers can be defined as a number that occurs in the hypothetical expression for the value of some quantized property of a subatomic particle, atom, or molecule and can only have certain integral or half-integral values.


The law of the quantization of the charge?

The principle that the electric charge of an object must equal an integral multiple of a universal basic charge.


What is meant by total normal electric induction over a surface?

It is the actually the electric flux i.e. integral Eds where E is electric field and ds is elemental area. It can be also defined as the no. of lines of force passing through a given area.


What does potential diffrence mean?

Potential Difference is the difference in electric potential energy per coulomb of charge at one point of a circuit compared to the charge at another point in a circuit. Potential difference, or voltage, is a way of describing the energy of an electric field without using test charges. In circuits, potential difference is the difference in voltage from one part of a circuit to another. It can also be described by ohms law where the Voltage=Current*Resistance In electrostatics, potential difference is the line integral of the electric field from one point to another with respect to distance.

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What is a difference of potential?

The simple answer: the potential at a point some distance, r from a monopole is kQ / r, where k is Coulumb's constant: 9.0E9 Q is the charge of the monopole and r is the distance from the monopole. And how to get there: Since electric force is kq1q2/ r2, the electric field ( Force per charge) is kQ/r2. The voltage of a particle is defined to be the integral of the electric field with respects to r. Thus integrating you get the above equation.


What is potential difference of a monopole?

The simple answer: the potential at a point some distance, r from a monopole is kQ / r, where k is Coulumb's constant: 9.0E9 Q is the charge of the monopole and r is the distance from the monopole. And how to get there: Since electric force is kq1q2/ r2, the electric field ( Force per charge) is kQ/r2. The voltage of a particle is defined to be the integral of the electric field with respects to r. Thus integrating you get the above equation.


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When electric flux is zero then electric field is also zero why?

The electric flux depends on charge, when the charge is zero the flux is zero. The electric field depends also on the charge. Thus when the electric flux is zero , the electric field is also zero for the same reason, zero charge. Phi= integral E.dA= integral zcDdA = zcQ Phi is zcQ and depends on charge Q, as does E.


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What is the anti-derivative of the absolute value of x over x?

For positive x, this expression is equal to 1. The integral (anti-derivative) is therefore x + C (where C is the arbitrary integration constant). For negative x, this expression is equal to -1, and the integral is -x + C. Wolfram Alpha gives the integral as x times sgn(x), where sgn(x) is the "sign" function.