Determined by the amount of energy a sound wave carries?

Answer 1

A radio going in the background will be radiating a few tens of milliWatts of sound from its speakers.

[Loudspeakers are rather inefficient, particularly so for high quality ones. 10% would be a good figure, - perhaps 3% for a high quality one.]

So a say 60 Watt (RMS) amplifier and appropriate speakers; which would sound really loud; would be radiating a few watts of sound.

Answer 2

Short Answer:

The energy in a specific sound can be measured but that is not the normal way of reporting sound energy.

Sound energy is typically characterized as power (energy per unit time) per unit area. The standard units (SI) of sound intensity are W/m2 (watts per square meter).

When sound is measured by a sound meter, the result is often reported as a "Sound intensity level" that is expressed in decibels and compared to a defined standard of one picowatt

per square meter.


Explanation:

Because sound lasts for some duration of time, the human sense of the sound is a sense at a particular point in time and so sound energy is usually characterized as the rate at which the sound energy is being transmitted. And, because sound is spread over a wide spatial domain, it is usually characterized by how much energy passes through a particular area of space. This naturally reflects the human experience of sound detected that enters the area provided by the human ear and the experience of sound "strength" depends on the specific amount of energy received in a time interval, i.e.

it depends on the rate at which energy of sound is delivered.

When we characterize sound energy, we normally measure sound intensity.
For the reasons stated above, the standard units (SI) of sound intensity are W/m2 (watts per square meter).

If a person wanted to know the total amount of energy in a given sound then the intensity would have to be added (integrated) over a surface and added (integrated) over the time of duration of the sound. That is fine, just not what is usually the most relevant quantification of sound energy.

More directly related to practical experience is the level of sound.
"Sound intensity level" or "acoustic intensity level" is a logarithmic measure of the sound intensity and is the "level" of sound which is different than the intensity. Sound intensity level is expressed in decibels and compared to a defined standard of one picowatt

per square meter.

The use of the decibel measure of sound reflect the way the sense of sound changes with intensity. In the most practical of circumstances, the "sone"

is a measure of the perceived loudness of sound and is used in a variety of commercial enterprises. It is not an official (SI) measure of sound.

Answer 3

A radio going in the background will be radiating a few tens of milliWatts of sound from its speakers.

[Loudspeakers are rather inefficient, particularly so for high quality ones. 10% would be a good figure, - perhaps 3% for a high quality one.]

So a say 60 Watt (RMS) amplifier and appropriate speakers; which would sound really loud; would be radiating a few watts of sound.

Answer 4

Energy is directly proportional to the frequency of a wave. The frequency times Planck's constant gives you the energy of a wave.

Answer 5

it is frequency an i know it by science class.

Answer 6

The amount of elctrical energy a wave carries is E=hf= hc/w = .2E-24 Joule meter/wavelength.

Answer 7

The loudness of a sound is determined by the amplitude of the sound wave, which represents the energy it carries. A greater amplitude corresponds to a louder sound.

Answer 8

loudness

Answer 9

Amplitude.