No- or minimal at best. Acceleration of the bullet comes from gas expanding inside the barrel, pushing the bullet. Once it leaves the barrel, (or within a VERY short distance) gas is no longer pushing, and acceleration stops, and bullet begins to slow from air resistance.
A bullet does not accelerate after it leaves the barrel of a gun. It will decelerate. You could say it accelerates, but the acceleration would be negative. The bullet is accelerated by expanding gas as it moves down the barrel, and after it leaves the muzzle, there is no more acceleration imparted from expanding gas. We also find that air friction (drag) is acting to slow it down. Think this one through and it becomes obvious.
There is no single answer to this question. It will depend on the cartridge, and the characteristics of the powder and bullet being fired. For instance, the 40 gr 22 Long Rifle cartridge accelerates from the moment of firing, until it travels about 12 inches. The gas produced by firing reaches it's max expansion, and the bullet now begins to SLOW to some degree from friction with the barrel. Acceleration is NOT uniform with any firearm cartridge- if graphed it would be a curve with a very sharp spike.
To find the force, we first need to calculate the acceleration of the bullet using the formula v^2 = u^2 + 2as, where v is the final velocity (322 m/s), u is the initial velocity (0 m/s since the bullet starts from rest), a is the acceleration, and s is the displacement (0.78 m). Solving for acceleration gives us approximately 161,589 m/s^2. Then, we can use Newton's second law (F = ma) to find the force, where m is the mass of the bullet (5.0 g = 0.005 kg) and a is the acceleration. The force exerted on the bullet during its travel down the barrel is approximately 807 N.
When a gun is fired, the force that affects the bullet as it leaves the barrel and travels through the air is the explosive force generated by the gunpowder igniting and rapidly expanding gases, propelling the bullet forward. This force propels the bullet through the barrel and imparts momentum to it, allowing it to overcome air resistance and travel towards its target.
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
A bullet does not accelerate after it leaves the barrel of a gun. It will decelerate. You could say it accelerates, but the acceleration would be negative. The bullet is accelerated by expanding gas as it moves down the barrel, and after it leaves the muzzle, there is no more acceleration imparted from expanding gas. We also find that air friction (drag) is acting to slow it down. Think this one through and it becomes obvious.
There is no single answer to this question. It will depend on the cartridge, and the characteristics of the powder and bullet being fired. For instance, the 40 gr 22 Long Rifle cartridge accelerates from the moment of firing, until it travels about 12 inches. The gas produced by firing reaches it's max expansion, and the bullet now begins to SLOW to some degree from friction with the barrel. Acceleration is NOT uniform with any firearm cartridge- if graphed it would be a curve with a very sharp spike.
A bullet leaves a gun barrel because it is forced out by the pressure of burning gasses.
It is the opening at the front of the gun where the bullet leaves the barrel.
It is the hole at the front end of the barrel where the bullet leaves the gun.
how fast it is going
No, a sabot slug does not rise after it leaves the barrel of a gun. No bullet rises after it leaves the barrel of a gun. It always falls from the line of sight of thebarrel. All firearms have to be "sighted in" a bit high to hit a target downrange. At close range, there is little time for a bullet to drop and hit "low" on the target. Down range, however, the drop is more significant. The more time a bullet is in flight, the more it drops below the line of sight of the barrel. But a bullet always begins to drop below the line of sight of the barrel after it leaves the muzzle. Always.
What causes it to rotate is the rifling in the barrel. What causes it to continue to rotate after it leaves the barrel is centrifugal force.
Rifling in the barrel is actually grooves cut into the barrel by the manufacturer to cause the bullet to spin as it leaves the barrel. Before rifling the bullets would tend to tumble when they left the barrel causing them to have shorter range and be less accurate.
To find the force, we first need to calculate the acceleration of the bullet using the formula v^2 = u^2 + 2as, where v is the final velocity (322 m/s), u is the initial velocity (0 m/s since the bullet starts from rest), a is the acceleration, and s is the displacement (0.78 m). Solving for acceleration gives us approximately 161,589 m/s^2. Then, we can use Newton's second law (F = ma) to find the force, where m is the mass of the bullet (5.0 g = 0.005 kg) and a is the acceleration. The force exerted on the bullet during its travel down the barrel is approximately 807 N.
When a gun is fired, the force that affects the bullet as it leaves the barrel and travels through the air is the explosive force generated by the gunpowder igniting and rapidly expanding gases, propelling the bullet forward. This force propels the bullet through the barrel and imparts momentum to it, allowing it to overcome air resistance and travel towards its target.
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.