yes
Yes, a steep slope on a displacement vs time graph indicates a large velocity. The slope of a displacement vs time graph represents the velocity of an object because velocity is the rate of change of displacement with respect to time. A steep slope implies that the displacement is changing rapidly over time, resulting in a large velocity.
The slope of the function on a displacement vs. time graph is (change in displacement) divided by (change in time) which is just the definition of speed. A relatively steep slope indicates a relatively high speed.
Yes, a steep slope on a displacement vs time graph indicates a large velocity. The slope represents the rate of change of displacement, which is velocity. A steeper slope indicates a higher velocity because the object is covering more distance in a shorter amount of time.
Not necessarily. The slope could be steep but negative, and since negative numbers are less than positive numbers, no. But in both cases, the magnitude of the velocity (speed) is great. Also, at each point in the displacement vs. time graph, you can only get instantaneous velocity. A curve on the graph will indicate an acceleration. The next antiderivative of acceleration is jerk. According to the Heisenberg uncertainty principle, the more certain you are of a particle's position OR velocity, the less certain you can be of the other property. On the displacement vs. time graph, either the particle is at a certain displacement and the velocity unknown, or the velocity between two points is known, but the displacement is unknown. That is, the velocity can be known between two points, but the particle resides somewhere between the two points at that time. The exact position is uncertain. Schroedinger had a cat. He put it in a box, and having no way to tell if the cat was alive or dead, it must be assumed to be both, simultaneously. But also because it is either alive or dead, and not both at once, yet also not partially one or the other, it must be assumed to also be neither at once. So Schroedinger's cat was both alive and dead, though it was neither. By corollary, the particle whose trajectory is described by the displacement vs. time graph has no velocity and has velocity at the same time.
It means a large acceleration, i.e. forward speed rapidly increasing or decreasing, or backward speed rapidly increasing. Note: It's really not possible to present a velocity-vs-time graph in any simple way. What you're looking at is a speed-vs-time graph.
Yes, a steep slope on a displacement vs time graph indicates a large velocity. The slope of a displacement vs time graph represents the velocity of an object because velocity is the rate of change of displacement with respect to time. A steep slope implies that the displacement is changing rapidly over time, resulting in a large velocity.
The slope of the function on a displacement vs. time graph is (change in displacement) divided by (change in time) which is just the definition of speed. A relatively steep slope indicates a relatively high speed.
Yes, a steep slope on a displacement vs time graph indicates a large velocity. The slope represents the rate of change of displacement, which is velocity. A steeper slope indicates a higher velocity because the object is covering more distance in a shorter amount of time.
Not necessarily. The slope could be steep but negative, and since negative numbers are less than positive numbers, no. But in both cases, the magnitude of the velocity (speed) is great. Also, at each point in the displacement vs. time graph, you can only get instantaneous velocity. A curve on the graph will indicate an acceleration. The next antiderivative of acceleration is jerk. According to the Heisenberg uncertainty principle, the more certain you are of a particle's position OR velocity, the less certain you can be of the other property. On the displacement vs. time graph, either the particle is at a certain displacement and the velocity unknown, or the velocity between two points is known, but the displacement is unknown. That is, the velocity can be known between two points, but the particle resides somewhere between the two points at that time. The exact position is uncertain. Schroedinger had a cat. He put it in a box, and having no way to tell if the cat was alive or dead, it must be assumed to be both, simultaneously. But also because it is either alive or dead, and not both at once, yet also not partially one or the other, it must be assumed to also be neither at once. So Schroedinger's cat was both alive and dead, though it was neither. By corollary, the particle whose trajectory is described by the displacement vs. time graph has no velocity and has velocity at the same time.
It means a large acceleration, i.e. forward speed rapidly increasing or decreasing, or backward speed rapidly increasing. Note: It's really not possible to present a velocity-vs-time graph in any simple way. What you're looking at is a speed-vs-time graph.
When acceleration is large, it means that the rate of change of velocity is significant. This could indicate that an object is speeding up or slowing down rapidly. The larger the acceleration, the quicker the change in velocity.
Large feet indicate that you will have more height. Large nose can be a genetic trait.
Graph plotter
Displacement hull.
That would depend on what you consider "large".The size of an object's momentum = (its mass) x (its speed).So, more mass and more speed result in more momentum.
False. Momentum is a product of an object's mass and velocity, so even if the object is small, it can have a large momentum if it has a high velocity. It doesn't need to be stationary to have a large momentum.
Displacement hull.