Does an object at rest have kinetic energy?

Answer 1

Easy! MV^2/2= MC^2 V^2=2(C^2) V=sqrt[2(c^2)] You can figure out the rest...

UPDATE: Actually, the guy who did the above is incorrect. It's not that easy: clearly V cannot equal the square root of 2c^2, because that would mean that the velocity of the particle exceeds the speed of light...and as we all know, nothing can travel faster than the speed of light. I'm currently trying to work out the answer myself...but can't. :( A3 You have to use the definition of relativistic KE to get a reasonable answer. KE = total mass energy - rest mass energy. So when KE = restmass energy you get total mass energy = 2x restmass energy. The formulas are then; mc^2 = 2m0c^2 m = 2m0 m0/sqrt{1-(v/c)^2} = 2m0 1/{1 - (v/c)^2} = 4 v = .866c , so when the velocity is .866 the speed of light the relativistic kinetic energy will equal rest mass energy m0c^2 .

Answer 2

nah, it may however have potential energy if it is sitting on a table for example (gravitational potential energy), in order for something to have kinetic energy it must be moving/ doing something

Answer 3

i think,it has no kinetic energy involve because a body at rest has its potential energy.

Answer 4

Kinetic Energy (KPE) is calculated using this equation:

KPE = (1/2)m.v^2

Where m is the mass and v is the velocity.

(You have to square the velocity)

Answer 5

Kinetic Energy is calculated using the equation KE = mv2/2

Since v = 0, KE = 0