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Does it mean a pencil is falling if you were in a freely falling elevator and you dropped a pencil and saw that the pencil was hovering?
In the unlikely event you find yourself in a freely-falling elevator, then the relative motion of the pencil is among the least of your concerns.
If the pencil were hovering, then both you and the pencil are in free-fall.
A condition that is not permanent for you and me, and it will eventually stop.
This is commonly referred to as zero gravity, but should be called zero net gravity, for in your space station, gravity still acts - but it is exactly balanced out by centrifugal force. If gravity actually became zero, then your space station would speed off into space.
What else can I help you with?
What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of gravity only (9.8ms2 )?
The force on the elevator while falling freely is equal to its weight, which is given by the formula F = m * g, where m is the mass of the elevator (1,000 kg) and g is the acceleration due to gravity (9.8 m/s^2). Therefore, the force on the elevator would be 1,000 kg * 9.8 m/s^2 = 9,800 N.
Does the magnet move as a freely falling object when it is dropped toward a conducting ring lying on the floor As the magnet falls toward the ring?
No, the magnet will not fall as a freely falling object when dropped toward a conducting ring. The magnet will experience resistance due to electromagnetic induction as it moves towards the conducting ring, which will slow down its descent. This is known as magnetic braking.
What is the velocity of freely falling objects 5 seconds after being dropped?
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
What are the examples of freely falling bodies?
Examples of freely falling bodies include an apple falling from a tree, a skydiver jumping out of a plane, and a rock dropped from a cliff. These objects fall under the influence of gravity with only the force of gravity acting upon them.
What is the force on a 1000 kg elevator that is falling freely at 9.8 msec2?
The force acting on the elevator is equal to its weight, which can be calculated using the formula F = m * g, where m is the mass of the elevator (1000 kg) and g is the acceleration due to gravity (9.8 m/s^2). So, the force on the elevator would be 1000 kg * 9.8 m/s^2 = 9800 N.
What is the period of a simple pendulum 80 cm long a- on earth and b- when it is in a freely falling elevator?
none. when there is gravity T=2pi square root of L/g but in a freely falling elevator, there is no accelerate so it doesn't have period the answer is none
Inside a freely-falling elevator would there be no apparent weight for you?
Yes, inside a freely-falling elevator, you would experience apparent weightlessness. This is because the elevator and everything inside it, including you, would be falling at the same rate due to gravity, creating the sensation of weightlessness.
What is the distance covered by a freely falling object 5 seconds after it is dropped from rest?
0.7848 meter
What is the force on a 1 000 kilogram-elevator that is falling freely under the acceleration of gravity only (9.8ms2 )?
The force on the elevator while falling freely is equal to its weight, which is given by the formula F = m * g, where m is the mass of the elevator (1,000 kg) and g is the acceleration due to gravity (9.8 m/s^2). Therefore, the force on the elevator would be 1,000 kg * 9.8 m/s^2 = 9,800 N.
What is the force on a kilogram elevator that is falling freely under the acceleration of gravity only?
That's the force that engineers call the "weight" of the elevator car. As long as the elevator stays on Earth, its weight is constant, whether it's rising, falling, stopped, or out of order. On or near the Earth's surface, the weight of 1,140 kilograms of mass is about 11,180 Newtons (2,513.3 pounds).
Does the magnet move as a freely falling object when it is dropped toward a conducting ring lying on the floor As the magnet falls toward the ring?
No, the magnet will not fall as a freely falling object when dropped toward a conducting ring. The magnet will experience resistance due to electromagnetic induction as it moves towards the conducting ring, which will slow down its descent. This is known as magnetic braking.
What is the velocity of freely falling objects 5 seconds after being dropped?
The velocity of a freely falling object 5 seconds after being dropped is approximately 49 meters per second (m/s) downwards. This is the velocity an object reaches due to the acceleration of gravity (9.8 m/s^2) acting on it.
What are the examples of freely falling bodies?
Examples of freely falling bodies include an apple falling from a tree, a skydiver jumping out of a plane, and a rock dropped from a cliff. These objects fall under the influence of gravity with only the force of gravity acting upon them.
What is the force on a 1000 kilogram elevator that is falling freely under the acceleration of gravity?
Force = mass * acceleration Since the only force acting on the elevator is gravity, the force is 1000*9.81 = 981N Towards the ground Note that it is essential to put the direction that the force is acting as it is a vector quantity.
What is the force on a 1000 kg elevator that is falling freely at 9.8 msec2?
The force acting on the elevator is equal to its weight, which can be calculated using the formula F = m * g, where m is the mass of the elevator (1000 kg) and g is the acceleration due to gravity (9.8 m/s^2). So, the force on the elevator would be 1000 kg * 9.8 m/s^2 = 9800 N.
What is the force on a 1140 kilogram elevator that is falling freely under the acceleration of gravity only?
That's the force that engineers call the "weight" of the elevator car. As long as the elevator stays on Earth, its weight is constant, whether it's rising, falling, stopped, or out of order. On or near the Earth's surface, the weight of 1,140 kilograms of mass is about 11,180 Newtons (2,513.3 pounds).
What is the period of a simple pendulum 80 cm long a on earth and b when it is in a freely falling elevator?
a) The period of a simple pendulum on Earth depends on the acceleration due to gravity, which is approximately 9.81 m/s^2. Using the formula for the period of a pendulum, T = 2pisqrt(L/g), where L is the length of the pendulum (80 cm = 0.8 m), we find T = 2pisqrt(0.8/9.81) ≈ 1.79 seconds. b) In a freely falling elevator, the acceleration due to gravity acts on both the elevator and the pendulum, so the period of the pendulum remains the same as on Earth, assuming no air resistance or other external factors.
