no
If two or more circuit elements are connected in series, the current must pass through each of them in turn. If two or more circuit elements are connected in parallel, that means there is a "fork in the road". In this case, part of the current will pass through one element, and part, through another one.
A bulb is not a conductor; it is actually an insulator. The glass or plastic casing of the bulb acts as a barrier to prevent the flow of electricity, allowing the electrical current to pass through the filament inside the bulb to produce light.
When resistors are connected in series, the flow of current through them is the same. This means that the current passing through each resistor is equal, as it has to pass through each resistor in the series circuit.
No, electricity cannot pass through a fused bulb because the filament inside the bulb is broken when it fuses, creating an open circuit that prevents the flow of electricity.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
initially when current pass through the filament
If two or more circuit elements are connected in series, the current must pass through each of them in turn. If two or more circuit elements are connected in parallel, that means there is a "fork in the road". In this case, part of the current will pass through one element, and part, through another one.
A bulb is not a conductor; it is actually an insulator. The glass or plastic casing of the bulb acts as a barrier to prevent the flow of electricity, allowing the electrical current to pass through the filament inside the bulb to produce light.
To determine the voltage required to pass 0.5 A of current through a 4.5-W bulb, you can use the formula P = V * I, where P is power, V is voltage, and I is current. Given that power is 4.5 W and current is 0.5 A, you can rearrange the formula to solve for voltage: V = P / I. Plugging in the values, V = 4.5 W / 0.5 A, which equals 9 volts. Therefore, 9 volts is required to pass 0.5 A of current through a 4.5-W bulb.
When resistors are connected in series, the flow of current through them is the same. This means that the current passing through each resistor is equal, as it has to pass through each resistor in the series circuit.
A 'series circuit' does that.
No, electricity cannot pass through a fused bulb because the filament inside the bulb is broken when it fuses, creating an open circuit that prevents the flow of electricity.
you probably have a bulb out or, check the wiring to that bulb if the bulb appears to be okay. If it is neither of those the connector may need to be cleaned. Sometimes they get a little oxidation on them and won't allow the current to pass through to the bulb. Good luck.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
Resistance in the circuit makes it difficult for current to pass through.
Yes, we can boil water if we pass enough current through it......
No, kerosene is an insulator and does not conduct electricity. Therefore, current does not pass through kerosene.