no
If two or more circuit elements are connected in series, the current must pass through each of them in turn. If two or more circuit elements are connected in parallel, that means there is a "fork in the road". In this case, part of the current will pass through one element, and part, through another one.
A bulb is not a conductor; it is actually an insulator. The glass or plastic casing of the bulb acts as a barrier to prevent the flow of electricity, allowing the electrical current to pass through the filament inside the bulb to produce light.
When resistors are connected in series, the flow of current through them is the same. This means that the current passing through each resistor is equal, as it has to pass through each resistor in the series circuit.
No, electricity cannot pass through a fused bulb because the filament inside the bulb is broken when it fuses, creating an open circuit that prevents the flow of electricity.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
initially when current pass through the filament
If two or more circuit elements are connected in series, the current must pass through each of them in turn. If two or more circuit elements are connected in parallel, that means there is a "fork in the road". In this case, part of the current will pass through one element, and part, through another one.
A bulb is not a conductor; it is actually an insulator. The glass or plastic casing of the bulb acts as a barrier to prevent the flow of electricity, allowing the electrical current to pass through the filament inside the bulb to produce light.
9 volts====================The question is a bit convoluted.The power dissipated by the bulb and the current through itboth depend on the voltage applied across it.In the real world, the way to ask this question would have to be:If a light bulb dissipates 4.5 W of power when 0.5 A of currentpasses through it, what voltage has been applied across it ?(And, for extra credit, what is the bulb's effective resistance ?)
When resistors are connected in series, the flow of current through them is the same. This means that the current passing through each resistor is equal, as it has to pass through each resistor in the series circuit.
A 'series circuit' does that.
No, electricity cannot pass through a fused bulb because the filament inside the bulb is broken when it fuses, creating an open circuit that prevents the flow of electricity.
you probably have a bulb out or, check the wiring to that bulb if the bulb appears to be okay. If it is neither of those the connector may need to be cleaned. Sometimes they get a little oxidation on them and won't allow the current to pass through to the bulb. Good luck.
If the bulb is removed from its holder, the circuit will be open, breaking the flow of electricity. This will result in the current being unable to pass through the circuit and the bulb will not light up as a result.
Yes, a bulb can glow if current passes through tomato juice, as it contains ions and electrolytes that can conduct electricity. However, the effectiveness of tomato juice as a conductor may vary, and it is unlikely to be as efficient as traditional conductive materials. The brightness of the bulb would depend on the concentration of the juice and the voltage applied.
Resistance in the circuit makes it difficult for current to pass through.
Yes, we can boil water if we pass enough current through it......