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We have a triangle with side lengths 6, 4, and 5 (the units are irrelevant). We want to know the size of the angle A formed between the sides of length 6 and 5. Use the cosine rule: 42 = 62 + 52 - 2(6x5)cosA 16 = 36 + 25 - 60cosA 16 = 61 - 60cosA 60cosA = 45 cosA = 0.75 So, A = arccos(0.75) or about 41.4 degrees, or 0.72 radians.

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