The current produced by a 1.5V flashlight cell would be lower than the current produced by a 12V car battery. This is because current is directly proportional to voltage in a circuit with constant resistance, following Ohm's Law (V = IR). Therefore, the higher voltage of the 12V car battery would result in a higher current compared to the 1.5V flashlight cell.
There is more energy in the battery than that given off as light and heat for two reasons. 1) Some energy is lost due to resistance in the battery. As current flows, energy is lost to heating of the battery due to this internal resistance. 2) As the battery operates, the voltage falls until it is too low to heat the bulb to incandescence. Yet energy remains in the battery, but this last energy is at too low a voltage to be useful.
There is more energy in the battery than that given off as light and heat for two reasons. 1) Some energy is lost due to resistance in the battery. As current flows, energy is lost to heating of the battery due to this internal resistance. 2) As the battery operates, the voltage falls until it is too low to heat the bulb to incandescence. Yet energy remains in the battery, but this last energy is at too low a voltage to be useful.
There is more energy in the battery than that given off as light and heat for two reasons. 1) Some energy is lost due to resistance in the battery. As current flows, energy is lost to heating of the battery due to this internal resistance. 2) As the battery operates, the voltage falls until it is too low to heat the bulb to incandescence. Yet energy remains in the battery, but this last energy is at too low a voltage to be useful.
The potential difference across the bulb in a flashlight should be slightly lower than the terminal voltage of the batteries used to power the flashlight. This is because there is a small internal resistance in the batteries which causes a voltage drop across it.
The amount of energy stored in the batteries is typically higher than the total amount of light output by the flashlight, as some energy is lost as heat during the conversion process. The efficiency of the flashlight will determine how much of the stored energy is actually converted into light.
No real comparison. In simplistic terms the D cell 1.5 volt flashlight battery will produce around 15 ampere hours. A 12 volt automobile battery will produce from 300 cold cranking amps (CCA) to 800 CCA or more.
They don't. Car batteries produce 100's of amps of current. a 1.5Volt flash light battery produces milli-amps at best.
12/1.5= 8. If I = Current from 1.5 Volt source and I2 = current from 12 V source then I = I2/8 or said in another way the current from 1.5V device is 1/8 of the current from 12 V device.
All of the energy in the battery, or most of it, is eventually given off as heat and light.
Do you mean the maximum possible current, or the current in normal applications? Car batteries have low internal resistance since auto starter motors draw a lot of current, a CCA (cold cranking amperage) rating of around 600A is not unusual for a car battery some can be even higher.A flashlight cell is not designed for that sort of current, while the maximum will depend on cell size and chemistry, I suspect a couple of amps might be a good guess at a maximum. However, the rechargeable NiCad or NiMH cells used in portable power tools can probably put out significantly more for short periods.Driving the same load resistance the current from a 12V battery will be 8 times that from a 1.5V battery. Assuming the load is not overloading the battery (and it might overload the flashlight cell if the resistance is too small).This is simple arithmetic: 12÷1.5=8
Do you mean the maximum possible current, or the current in normal applications? Car batteries have low internal resistance since auto starter motors draw a lot of current, a CCA (cold cranking amperage) rating of around 600A is not unusual for a car battery some can be even higher.A flashlight cell is not designed for that sort of current, while the maximum will depend on cell size and chemistry, I suspect a couple of amps might be a good guess at a maximum. However, the rechargeable NiCad or NiMH cells used in portable power tools can probably put out significantly more for short periods.Driving the same load resistance the current from a 12V battery will be 8 times that from a 1.5V battery. Assuming the load is not overloading the battery (and it might overload the flashlight cell if the resistance is too small).This is simple arithmetic: 12÷1.5=8
Do you mean the maximum possible current, or the current in normal applications? Car batteries have low internal resistance since auto starter motors draw a lot of current, a CCA (cold cranking amperage) rating of around 600A is not unusual for a car battery some can be even higher.A flashlight cell is not designed for that sort of current, while the maximum will depend on cell size and chemistry, I suspect a couple of amps might be a good guess at a maximum. However, the rechargeable NiCad or NiMH cells used in portable power tools can probably put out significantly more for short periods.Driving the same load resistance the current from a 12V battery will be 8 times that from a 1.5V battery. Assuming the load is not overloading the battery (and it might overload the flashlight cell if the resistance is too small).This is simple arithmetic: 12÷1.5=8
Do you mean the maximum possible current, or the current in normal applications? Car batteries have low internal resistance since auto starter motors draw a lot of current, a CCA (cold cranking amperage) rating of around 600A is not unusual for a car battery some can be even higher.A flashlight cell is not designed for that sort of current, while the maximum will depend on cell size and chemistry, I suspect a couple of amps might be a good guess at a maximum. However, the rechargeable NiCad or NiMH cells used in portable power tools can probably put out significantly more for short periods.Driving the same load resistance the current from a 12V battery will be 8 times that from a 1.5V battery. Assuming the load is not overloading the battery (and it might overload the flashlight cell if the resistance is too small).This is simple arithmetic: 12÷1.5=8
There is more energy in the battery than that given off as light and heat for two reasons. 1) Some energy is lost due to resistance in the battery. As current flows, energy is lost to heating of the battery due to this internal resistance. 2) As the battery operates, the voltage falls until it is too low to heat the bulb to incandescence. Yet energy remains in the battery, but this last energy is at too low a voltage to be useful.
There is more energy in the battery than that given off as light and heat for two reasons. 1) Some energy is lost due to resistance in the battery. As current flows, energy is lost to heating of the battery due to this internal resistance. 2) As the battery operates, the voltage falls until it is too low to heat the bulb to incandescence. Yet energy remains in the battery, but this last energy is at too low a voltage to be useful.
Flashlight is not good model to test sun light hit earth. The light of flashlight is too small energy to compare sun light.
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