0
What else can I help you with?
How much force does an 70kg astronaunt exert on his chair while accelerating up at 19m?
The force exerted would be equivalent to the astronaut's mass multiplied by the acceleration due to gravity. Therefore, the force would be 70kg * 19m/s^2, which equals 1330 N.
What force is necessary to accelerate at 70kg object at a rate of 4.2 minutes per seconds?
To accelerate a 70kg object at a rate of 4.2 m/s^2, you would need a force of 294 Newtons. This is calculated using Newton's second law, F = m*a, where F is the force, m is the mass of the object (70kg), and a is the acceleration (4.2 m/s^2).
What if the impact force of a 70kg man falling .85 meters?
The impact force of a 70kg man falling 0.85 meters can be calculated using the formula F=mgd, where F is the force, m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and d is the distance fallen. Plugging in the values, the impact force would be approximately 576.5 Newtons.
What is the landing force of a 70kg man falling .85 meters?
The force of impact when a 70kg man falls 0.85 meters can be calculated using the formula F = m * g * h, where F is the force, m is the mass (70 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height (0.85 m). Plugging in the values, the force of impact would be approximately 570.15 N.
What is a persons weight in newtons that has a mass of 70 kilograms?
A person with a mass of 70 kilograms would weigh approximately 686 Newtons on Earth. This is calculated by multiplying the mass in kilograms by the acceleration due to gravity, which is approximately 9.81 m/s^2.
How much force does an 70kg astronaunt exert on his chair while accelerating up at 19m?
The force exerted would be equivalent to the astronaut's mass multiplied by the acceleration due to gravity. Therefore, the force would be 70kg * 19m/s^2, which equals 1330 N.
What force is necessary to accelerate at 70kg object at a rate of 4.2 minutes per seconds?
To accelerate a 70kg object at a rate of 4.2 m/s^2, you would need a force of 294 Newtons. This is calculated using Newton's second law, F = m*a, where F is the force, m is the mass of the object (70kg), and a is the acceleration (4.2 m/s^2).
How do you calculate the gain in potential energy a 70kg mass travelling up a lift of 840m and a rise of 240m.Journey takes 2mins acceleration due to gavity is 9.8ms2?
140.519
What if the impact force of a 70kg man falling .85 meters?
The impact force of a 70kg man falling 0.85 meters can be calculated using the formula F=mgd, where F is the force, m is the mass, g is the acceleration due to gravity (9.8 m/s^2), and d is the distance fallen. Plugging in the values, the impact force would be approximately 576.5 Newtons.
What is the landing force of a 70kg man falling .85 meters?
The force of impact when a 70kg man falls 0.85 meters can be calculated using the formula F = m * g * h, where F is the force, m is the mass (70 kg), g is the acceleration due to gravity (9.81 m/s^2), and h is the height (0.85 m). Plugging in the values, the force of impact would be approximately 570.15 N.
What is the weight if the mass is 70 kg?
Weight = mass*g, where g is the acceleration due to gravity. W = 70kg*9.807m/s^2 = 686.49 N (Newtons of force)
Is it true that the attractive force of a 70kg person exerts on the Earth is smaller than the force the earth exerts on the person?
No, the force of gravity between the Earth and a 70kg person is the same, according to Newton's third law of motion. The force exerted by the person on the Earth is equal in magnitude to the force exerted by the Earth on the person.
What is Trey Songz's weight?
70kg
What is a persons weight in newtons that has a mass of 70 kilograms?
A person with a mass of 70 kilograms would weigh approximately 686 Newtons on Earth. This is calculated by multiplying the mass in kilograms by the acceleration due to gravity, which is approximately 9.81 m/s^2.
How much force is needed to lift 70kg box with an 2 minutes per seconds acceleration of the box?
momentum is mass x velocity (p=mv), and velocity is distance divided by time (d/t),so p=m(d/t)=(70kg)(400m/50s)=560 kgm/s================================Answer #2:If the questioner actually knew what he was talking about when he postedthe question, then the runner's average momentum is(70 kg) x (400 miles) x(1,609.344 meters/mile)/(50 seconds) = 9.012 x 105kg-m/secWe can't help but notice that in the question's frame of reference, the runner issteaming along at 28,800 miles per hour. This arouses our curiosity, but is notgermaine to the problem or to its solution, and we play the hand we are dealt.Our math and physics are bullet-proof, and we stand by them.
What is the force on a 70kg person decelerating at a rate of 9.8 meters per second squared?
F=ma=70x9.8=686N
Find the momentum of a 70kg runner?
The momentum of a 70kg runner can be calculated by multiplying the mass of the runner (70kg) by the velocity of the runner. Without the velocity, we cannot determine the momentum.
