The surface area of a circle is calculated as Area = pi x radius2. If the radius is in meters, the area will be in square meters.
The surface area of a circle is calculated as Area = pi x radius2. If the radius is in meters, the area will be in square meters.
The surface area of a circle is calculated as Area = pi x radius2. If the radius is in meters, the area will be in square meters.
The surface area of a circle is calculated as Area = pi x radius2. If the radius is in meters, the area will be in square meters.
The surface area of a circle is calculated as Area = pi x radius2. If the radius is in meters, the area will be in square meters.
F=m*am1=2*m2f2/m2= a =f1/m1f2/m2 = f1/(2*m2)f2 = f1*m2/(2*m2)f2 = f1/2
The initial momentum is M1U1 + M2U2 where M1 and M2 are the masses of the two cars (in kilograms), and U1 and U2 are their velocities (in metres per second).
about 4kg/m2
1 Pascal (Pa) = 1 newton per meter214 Pa = 14 N/m2(14 N/m2) times (2 m2) = 28 Newtons
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
Area is 4.6 m2
Area is 4.6 m2
Area of circle = pi*r2 where r is the radius. Area = pi*1.42 = 6.16 m2 (to 2 dp)
Multiply m by m.
A = 380.13 m2
10.1787602 m2
A = 141.03 m2
A = 441,790 m2
A = 128.28 m2
A = 45.8 m2
A = 33.18 m2
A = 282,740 m2