You look up the specific heat of copper (per mass unit). Then you multiply specific heat x mass x temperature difference.
1.18x10^4j
The question is : A 2000W electric heater supplies energy to 0.5kg copper kettle containing 1kg of water. calculate time taken to raise the temperature by 10 degree
energy is calculated in "jouls"
by adding potential energy and kinetic energy, you get mechanical energy.
electrical wire
You cannot. You need the mass of the piece of copper.
1.18x10^4j
O.385x1x2=0.77 Answer: 0.77
To find the energy needed to raise the temperature of a substance, we can use the equation Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. For copper, the specific heat capacity is approximately 0.386 J/g°C. Converting the mass from grams to kilograms (50 g = 0.05 kg), we can plug in the values to calculate the energy: Q = (0.05 kg) * (0.386 J/g°C) * (30°C) = 0.579 J Therefore, you would need approximately 0.579 joules of energy to raise the temperature of 50 grams of copper by 30 degrees Celsius.
You calculate the new kinetic energy, you calculate the old kinetic energy, then you subtract.
The question is : A 2000W electric heater supplies energy to 0.5kg copper kettle containing 1kg of water. calculate time taken to raise the temperature by 10 degree
Only by an insignificant amount due to the mass-energy equivalence (from the Theory of Relativity). If you are interested in this, calculate the energy increment (in Joules) and divide it by the square of the speed of light (in meters/second). The resulting mass increment will be in kilograms.
energy is calculated in "jouls"
q = mass * specific heat * change in temperature 428 joules = (mass)(0.385 J/gC)(25o C) = 44 grams copper ============
No. Copper is a good conductor of both electricity and heat.
Silver, copper
No you cannot because copper is an extremely well conductor, which implies that energy would simply follow through the copper without dissipating much energy, it would not light up.