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What else can I help you with?
How would you estimate the size of object viewed under high power objective lens 40 times if you were given the size of the field diameter when using low power objective lens 4 times?
You can estimate the size of the object by comparing the field diameters observed under the low power objective lens (4x) and high power objective lens (40x). Calculate the ratio of the field diameters (40x/4x = 10), and use this ratio to estimate the size of the object viewed under the high power objective lens. Simply multiply the size of the object viewed under the low power objective lens by the ratio (field diameter at 4x) to get an estimation.
Why are you never to use the adjustment knob with high or medium power?
Using the adjustment knob at high or medium power can damage the lenses or specimen due to the sudden movement of the lens away from the specimen, as the depth of field is significantly reduced at higher magnifications. It is better to focus at low power first to bring the specimen into focus, then switch to higher magnification and use fine focus for adjustment.
A motorcycle generates 500W of power The torque is 50.0 N m What is the angular velocity?
General formula used to calculate torque from power is torque=power*9.55/rpm so,using your data,50=500*9.55/N(rpm) i.e.,N(rpm)=95.5rpm. Angular Velocity=3.147*d*N/60 Unless the diameter is unknown its not possible to calculate the angular velocity.Once diameter is known it can substituted in the above mentioned formula.
How do you calculate force and power for electromagnet?
To calculate the force produced by an electromagnet, you can use the formula: Force (N) = magnetic field strength (T) x current (A) x length of the conductor (m). Power can be calculated using the formula: Power (W) = current (A) x voltage (V). Make sure to consider the properties of the specific electromagnet and the materials involved in your calculations.
What instrument measures power?
For direct measurement of power in field installation, test, and maintenance of radio communications facilities, we use a device called an RF "power meter".
How big is the worm relative to the diameter of the field of view?
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power
How do you determine the diameter of the field of view?
At low power on the compound microscope, the diameter of the field of view is 4 millimeters. This is reduced to 1.7 millimeters when you switch to medium power and further reduced to 0.4 millimeters when you switch to high power. Covert the measurment for the field of view from millimeters to microns, the conventional unit of measurment in microscopy. There are 1000 microns in one millimeter. Low power: 4mm= 4,000um Medium power: 1.7mm= 1,700um High power: 0.4mm= 400um
Under high power magnification the field diameter is 400 calculate the size of the organism?
To calculate the size of the organism, you would need to know the magnification of the microscope being used. Comparing the field diameter at 400x magnification with the actual size of the organism would give you the scale factor to determine the organism's size. For example, if the field diameter at 400x is 0.5 mm, and the actual size is 50 micrometers, then the organism is 10 times smaller than the field diameter.
What is the diameter of the high power field of a microscope in micrometers?
the diameter of the high power field microscope is 500 micrometers
What is cell is approximately 13 the diameter of the field of vision using high power and the diameter of the field of vision for high power is 600 micrometers what is the size of this?
To find the size of the cell, you can divide the diameter of the field of vision by 13. Given that the diameter of the field of vision at high power is 600 micrometers, the calculation would be: 600 micrometers / 13 ≈ 46.15 micrometers. Therefore, the size of the cell is approximately 46.15 micrometers.
What happens to the diameter of the field of the view when you change for low to high power?
The diameter of the field of view decreases when changing from low to high power magnification. This is because higher magnification zooms in closer on the specimen, limiting the area of the specimen that can be seen at one time.
What is the diameter when you have 1.2mmhigh power filed and an object that occupies one third of that field?
To find the diameter of the field of view at high power, you can use the height of the field. If the field is 1.2 mm high and the object occupies one third of that field, then the height of the object is 0.4 mm (1.2 mm / 3). The diameter of the field of view is equal to the height when viewed in a circular field, so it remains 1.2 mm.
What is the field of view for medium power on a compound light microscope?
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A unicellular organism takes up one third of the field of view at medium power what is the actuall size of the organism?
The actual size of the unicellular organism would depend on the total field of view at medium power on the microscope. Without knowing the specific magnification and field of view of the microscope, it is difficult to determine the actual size of the organism.
What happens to the diameter when you go from low to high power?
When you switch from low to high power on a microscope, the diameter of the field of view decreases because the high-power objective has a higher magnification, which zooms in on a smaller area. This allows for more detailed observation of the specimen at the expense of a smaller field of view.
How would you estimate the size of object viewed under high power objective lens 40 times if you were given the size of the field diameter when using low power objective lens 4 times?
You can estimate the size of the object by comparing the field diameters observed under the low power objective lens (4x) and high power objective lens (40x). Calculate the ratio of the field diameters (40x/4x = 10), and use this ratio to estimate the size of the object viewed under the high power objective lens. Simply multiply the size of the object viewed under the low power objective lens by the ratio (field diameter at 4x) to get an estimation.
How can you calculate the flow of FD fan and motor power when you know fan speed and impeller diameter?
times by 2
