Angular speed is calculated by dividing the linear speed by the radius. If the radius is unknown, you would not be able to directly find the angular speed without more information about the motion.
To find the linear velocity from angular velocity, you can use the formula: linear velocity angular velocity x radius. This formula relates the speed of an object moving in a circle (angular velocity) to its speed in a straight line (linear velocity) based on the radius of the circle.
A ball at the end of a 0.75 m string rotating at constant speed in a circle has an angular velocity of (2 pi) divided by (time to complete one revolution). Time to complete one revolution = (speed) divided by (2 times pi times radius). If you write this algebraically and then simplify the fraction, you find that the angular velocity is (4 times pi2 times radius) divided by (speed) = (29.609/speed) radians/sec. The speed is expressed in meters/sec. The solution doesn't depend on the orientation of the plane of the circle.
The acceleration of the particle moving in a circular path is given by the formula a = rω^2, where r is the radius of the circle and ω is the angular speed. Plugging in the values, a = (1.5 m)(rads/s)^2 = 2.25 m/s^2.
To find the instantaneous angular acceleration, you need to know the time rate of change of the instantaneous angular velocity. Without this information, you cannot calculate the instantaneous angular acceleration at t=5.0s.
The linear velocity of the points on the outside of gear 2 can be converted to angular velocity by dividing by the radius of gear 2. This relationship is given by the formula: angular velocity = linear velocity / radius. By plugging in the values for linear velocity and radius, you can calculate the angular velocity of gear 2.
To find the linear velocity from angular velocity, you can use the formula: linear velocity angular velocity x radius. This formula relates the speed of an object moving in a circle (angular velocity) to its speed in a straight line (linear velocity) based on the radius of the circle.
A ball at the end of a 0.75 m string rotating at constant speed in a circle has an angular velocity of (2 pi) divided by (time to complete one revolution). Time to complete one revolution = (speed) divided by (2 times pi times radius). If you write this algebraically and then simplify the fraction, you find that the angular velocity is (4 times pi2 times radius) divided by (speed) = (29.609/speed) radians/sec. The speed is expressed in meters/sec. The solution doesn't depend on the orientation of the plane of the circle.
The acceleration of the particle moving in a circular path is given by the formula a = rω^2, where r is the radius of the circle and ω is the angular speed. Plugging in the values, a = (1.5 m)(rads/s)^2 = 2.25 m/s^2.
Assuming that "r" is the radius, that simply isn't sufficient information to calculate angular velocity.
To find the instantaneous angular acceleration, you need to know the time rate of change of the instantaneous angular velocity. Without this information, you cannot calculate the instantaneous angular acceleration at t=5.0s.
The linear velocity of the points on the outside of gear 2 can be converted to angular velocity by dividing by the radius of gear 2. This relationship is given by the formula: angular velocity = linear velocity / radius. By plugging in the values for linear velocity and radius, you can calculate the angular velocity of gear 2.
from power= torque*angular speed u can calculate torque and from torque u can find the force if the radius is known.
1 revolution = 2PI radian. 2 revolutions = 4PI radian The angular speed of the Ferris wheel is 4PI radians . Multiply by the radius. The linear speed is 100PI feet per minute.
a protractor
power=torque x speed p=txn 5000w= torque x angular speed if the speed of rotation is known, then from above formula we can find the minimum torque required to run the generator.
Take the circumference divided by pi to find the diameter and divide the diameter by two to find the radius.
What we've got here is a particle rotating around an axis some distance fromit. So its angular momentum is ( r X m v ), and the fact that the particlehappens to be a ball is irrelevant.The vector cross-product just says that the direction of the angular momentumvector will be perpendicular to the plane of the rotation, which I don't think we careabout for purposes of this question. We're just looking for its magnitude . . . r m v .r = radius of the rotationm = massv = speed around the circle = ( ω r )r m v = (r m) (ωr) = m ω r2 = (0.210) (10.4) (1.1)2 = 2.64264 kg-m2/secI have no feeling for whether or not that's a reasonable result. I lost it aroundthe last time I had to calculate an angular momentum ... an event that wasroughly contemporaneous with the mass extinction of the dinosaurs.