The depth of an object in water can be found by measuring the distance between the surface of the water and the top of the object. This can be done using tools such as a measuring tape, ruler or depth gauge. Submerge the tool next to the object in water and note the measurement to determine the depth.
The apparent depth of an object submerged in water can be calculated using the formula: apparent depth = real depth / refractive index. Since the refractive index of water is approximately 1.33, the apparent depth of an object 5 meters below the water surface would be around 3.76 meters.
35000 feet of altitude exerts more pressure on an object compared to 260 feet of water depth. This is because the pressure exerted by the atmosphere decreases as altitude increases, while the pressure exerted by water increases as depth increases.
If you try to find the density of an object with a density less than water, the object will float in water. This indicates that the object is less dense than water. To find the density of such an object, you would divide the mass of the object by its volume.
To find the density of an object in water, first measure the mass of the object using a scale. Then, measure the volume of the water displaced by the object when it is submerged. Divide the mass of the object by the volume of water displaced to calculate the density of the object in water.
As depth increases, the pressure on an object also increases. This increased pressure compresses air in the object, thus reducing its volume. This reduction in volume causes the object to displace less water, resulting in a decrease in buoyant force.
The apparent depth of an object submerged in water can be calculated using the formula: apparent depth = real depth / refractive index. Since the refractive index of water is approximately 1.33, the apparent depth of an object 5 meters below the water surface would be around 3.76 meters.
To find the difference between the initial and final depth of water is to subtract the final depth by the initial depth. The initial depth of what is what the water depth starts at and the final depth is the depth of the water once it is finished filling up.
35000 feet of altitude exerts more pressure on an object compared to 260 feet of water depth. This is because the pressure exerted by the atmosphere decreases as altitude increases, while the pressure exerted by water increases as depth increases.
It is called buoyant force. It is calculated by determining the volume of water displaced by the object, which is the volume of the object under water.The weight of this quantity of water is the buoyant force. It can also be calculated by knowing the depth of the object in the water, the pressure at that depth, and the area of the bottom of the object. Buoyant Force = Pressure * depth It can also be calculated by knowing the weight of the object. If an object is floating the water is supporting the object's weight. So the buoyant force = weight of object
WAY 1: multiplying are and the depth of an object WAY 2: dividing weight by the density of an object
length signifies how long the object is while depth signifies the deepness or height of the object .there is no difference in depth and height of an object
If you try to find the density of an object with a density less than water, the object will float in water. This indicates that the object is less dense than water. To find the density of such an object, you would divide the mass of the object by its volume.
To find the density of an object in water, first measure the mass of the object using a scale. Then, measure the volume of the water displaced by the object when it is submerged. Divide the mass of the object by the volume of water displaced to calculate the density of the object in water.
Depth of water
Volume = With times Depth times Hieght. V= WDH
you have to check it every 4 hours
As depth increases, the pressure on an object also increases. This increased pressure compresses air in the object, thus reducing its volume. This reduction in volume causes the object to displace less water, resulting in a decrease in buoyant force.