You measure it. Depending on the information provided, you can also calculate it, for example using trigonometry.
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Work done= Force vector . Displacement vector=Force*displacement*cos a, where a is the angle between the force and the displacement. So you have the values of work force and displacement then you can do the cosine inverse of the ratio of work done to the product of the force and displacement. That will give you the angle.
You can find the work done on an object by multiplying the force applied to the object by the distance over which the force is applied, and then multiplying that by the cosine of the angle between the force and the direction of motion. The formula is work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
Work done can be calculated using the formula: work = force * distance * cos(theta), where theta is the angle between the force and the direction of movement. The time interval does not play a direct role in determining work done. However, if you know the power (work done over time), you can calculate work done by multiplying power by time.
The work done when pushing a crate with a force N across a distance M on a floor depends on the angle between the force and the direction of motion. If the force is applied in the same direction as motion, work done is N * M. If the force is applied at an angle, work done is N * M * cos(theta), where theta is the angle between the force and direction of motion.
The work done when a person is holding a pail and moving forward by a force F is given by the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is directly in line with the direction of motion (theta = 0), then all of the force is doing work. If the force is at an angle to the direction of motion, only the component of the force in the direction of motion contributes to the work done.
When you apply force at an angle to the direction of movement, two components result; F.D + FxD. F.D = -FDcos(angle) called work and FXD = FDsin(angle) called torque.
If the angle between the displacement and force applied is less than a right angle, then it is Positive Work done. If the angle between the displacement and the force applied is greater than a right angle then it is Negative Work done. If the displacement and force are at right angles, or either is zero, then it is Zero Work done.
the formula F.S cos angle is used (the dot product) so if angle is 0,cos angle=1 hence work done is positive and maximum if angle is 90 so cos 90 is 0 hence work done is minimum if work done is negative the angle is 180 The work done by friction is always negative (opposite the force) Since work is force x displacement, a negative value for work could mean that the displacent was negative
You can find the work done on an object by multiplying the force applied to the object by the distance over which the force is applied, and then multiplying that by the cosine of the angle between the force and the direction of motion. The formula is work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
When The Work Done is Zero Percent and it happens in 90 Angle.
Work is minimized when the angle between the force applied and the direction of motion is 90 degrees (or π/2 radians). At this angle, the force does not contribute to the displacement in the direction of the force, resulting in zero work done. In general, as the angle increases from 0 to 90 degrees, the work done decreases, reaching its minimum at 90 degrees.
Work done can be calculated using the formula: work = force * distance * cos(theta), where theta is the angle between the force and the direction of movement. The time interval does not play a direct role in determining work done. However, if you know the power (work done over time), you can calculate work done by multiplying power by time.
POSITIVE work is done when the direction of displacement and gravitational force is same. This makes an angle of zero degrees. Fd?FScos0 equals +1. The work done is positive.
The work done when pushing a crate with a force N across a distance M on a floor depends on the angle between the force and the direction of motion. If the force is applied in the same direction as motion, work done is N * M. If the force is applied at an angle, work done is N * M * cos(theta), where theta is the angle between the force and direction of motion.
The work done when a person is holding a pail and moving forward by a force F is given by the formula: Work = Force x Distance x cos(theta), where theta is the angle between the force and the direction of motion. If the force is directly in line with the direction of motion (theta = 0), then all of the force is doing work. If the force is at an angle to the direction of motion, only the component of the force in the direction of motion contributes to the work done.
When you apply force at an angle to the direction of movement, two components result; F.D + FxD. F.D = -FDcos(angle) called work and FXD = FDsin(angle) called torque.
The rotational work formula is W , where W represents the work done in rotational motion, is the torque applied, and is the angle through which the object rotates. This formula is used to calculate the work done in rotational motion by multiplying the torque applied to an object by the angle through which it rotates.
Work done is zero when force acts right angle to the direction of the motion of the body . my situation of zero work done , one day i hold many books approximately 15 after some time i feel very tired but there is a physical work done is zero because i worked against right angle . i feel actual work is done because when i holding book my muscles and blood circulate all over the body so i feel work is done. Arshad Quraishi