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The case you're describing is called an inelastic collision.

Two objects collide, stick to each other and continue their motion as one body.

Due to momentum conservation principle, sum of two bodies momenta before collision has to be equal to momentum of the one body after collision.

pbefore = pfirst + psecond = m1v1 + m2v2

pafter = (m1 + m2)vcommon

Since pbefore = pafter,

(m1 + m2)vcommon = m1v1 + m2v2

We can get vcommon from that:

vcommon = (m1v1 + m2v2) / (m1 + m2)

[vi are velocities of bodies before collision and vcommon is a velocity after collision]

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16y ago

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