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It is very simple. First let us fix a pin at the bottom of an empty beaker. Now focus at the pin and note down the reading in the vertical scale as R1. Now pour the given liquid and once again focus the pin and note down the reading R2. Now sprinkle saw dust over the surface of liquid and focus at the dust and note down the reading R3.

Now refractive index of the liquid = actual depth / apparent depth

So mu of liquid = R3-R1 / R3-R2

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12y ago

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