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Assuming the the object was dropped and is relatively close to the earth's surface; then we can say that since:

distance=(1/2)(acceleration)(time)2 ; 10m=(1/2)(9.8)(time)2 ; then the time spent falling is apprx. 1.429s, multiplied by the acceleration (9.8 m/s2) gives us a velocity of apprx. 14.00 m/s

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