0
Air resistance can affect the measurement of the acceleration due to gravity (g) by slowing down the fall of a free-falling object. This can result in a lower acceleration value than the actual value. To minimize the impact of air resistance, experiments are often conducted in a vacuum to ensure more accurate measurements of g.
What else can I help you with?
An object that is thrown vertically upward will return to its original position with the same speed as it had initially if air resistance is negligible if air resistance is appreciable?
As an object rises WITH air resistance, the acceleration is larger in size than g, because both gravity and air resistance will be causing a downward acceleration. As the object FALLS with air resistance, the acceleration will be smaller in size than g, because gravity and resistance will be opposing each other. Because of the smaller acceleration being applied over the same distance, the return speed will be slower than the launch speed.
What three factors affect the amount of air resistance from the force of gravity?
(Forces in newtons)The (constant) force down on a freefalling body is : mass (kg) * acceleration due to gravity ((m/s)/s) .The force of air resistance up is : velocity2 * drag coefficient .>The net force is the difference between the two .>Acceleration at any given velocity is given by net force / mass .>Terminal velocity is where the down and upforces balance .>>Drag coefficient can be calculated if terminal velocity, mass and acceleration due to gravity (g) are known.Example:Terminal velocity = 70 m/s, Mass = 70 kg, g = 9.82 (m/s)/sThen >force down = 70 * 9.82 = 687.4 newtonsforces are equal at terminal velocity so air resistance = 687.4 newtons @ 70 m/sSo >687.4 = v2 * drag coefficientSo >drag coefficient = 687.4 / v2 = 0.14 (approx) .
A 2kg is dropper from a height of 1000m what is the force of air resistance on the obhect when it raches terminal velocity?
When it reaches terminal velocity it is not accelerating. According to newton's 2nd law, if acceleration = 0, then Net force = 0 If we call up to be positive direction Net force = -mg + Force air resistance = 0 So the air resistance force would be equal in magnitude to m*g and opposite in direction. m is mass of object, g is about 9.81 for objects near earths surface
Can anything ever have a downward acceleration greater than g?
Yes, objects can accelerate at a rate greater than "g". Most objects, when falling in the absense of air resisitance, accelerate at a uniform rate of -9.81 m/s^2 (this is under ideal conditions on Earth). Air resistance tends to decrease that acceleration. The classic example of greater than "g" acceleration is a bungee jumper.
Does a rock falling from a cliff have a constant acceleration?
Yes. Every body that is falling, (if there is no other force then the gravity force) will fall in constant acceleration. Mass does not affect the acceleration of the body. According to Newton's second law: F=m*a m*g=m*a g=a F= Force m= mass a= acceleration g= gravity acceleration m*g= the force of gravity
What has the author G F Tagg written?
G. F. Tagg has written: 'Earth resistances' 'The practical measurement of insulation resistance' -- subject(s): Electric insulators and insulation, Electric resistance, Testing
If a projectile is shot in the air neglecting air resistance what is its vertical accelrration?
the vertical accelaration in case of a projectile is 'g'.
An object that is thrown vertically upward will return to its original position with the same speed as it had initially if air resistance is negligible if air resistance is appreciable?
As an object rises WITH air resistance, the acceleration is larger in size than g, because both gravity and air resistance will be causing a downward acceleration. As the object FALLS with air resistance, the acceleration will be smaller in size than g, because gravity and resistance will be opposing each other. Because of the smaller acceleration being applied over the same distance, the return speed will be slower than the launch speed.
What three factors affect the amount of air resistance from the force of gravity?
(Forces in newtons)The (constant) force down on a freefalling body is : mass (kg) * acceleration due to gravity ((m/s)/s) .The force of air resistance up is : velocity2 * drag coefficient .>The net force is the difference between the two .>Acceleration at any given velocity is given by net force / mass .>Terminal velocity is where the down and upforces balance .>>Drag coefficient can be calculated if terminal velocity, mass and acceleration due to gravity (g) are known.Example:Terminal velocity = 70 m/s, Mass = 70 kg, g = 9.82 (m/s)/sThen >force down = 70 * 9.82 = 687.4 newtonsforces are equal at terminal velocity so air resistance = 687.4 newtons @ 70 m/sSo >687.4 = v2 * drag coefficientSo >drag coefficient = 687.4 / v2 = 0.14 (approx) .
How many ounces in a g?
What is a 'g' . -No recognised measurement that name.
What is the g for in food measurement?
Quantities with a 'g' after them are measurements in grams.
What is the standard measurement for the US?
G's
What measurement is g cm3?
Volume
A 2kg is dropper from a height of 1000m what is the force of air resistance on the obhect when it raches terminal velocity?
When it reaches terminal velocity it is not accelerating. According to newton's 2nd law, if acceleration = 0, then Net force = 0 If we call up to be positive direction Net force = -mg + Force air resistance = 0 So the air resistance force would be equal in magnitude to m*g and opposite in direction. m is mass of object, g is about 9.81 for objects near earths surface
How many significant figures are in the measurement 0.20 g?
There are 2 significant figures in this measurement.
Find the greatest possible error for the measurement 0.991 g?
The greatest possible error for the measurement 0.991 g would be half of the smallest measurable unit, which is typically 0.001 g for this measurement. Therefore, the greatest possible error would be ±0.0005 g.
What does g stand for in metric measurement?
gram
