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It looks to me like
Acceleration of gravity = G M / R2
The 'M' contributing to the acceleration is the 'M' inside the 'R' of interest. If the earth is homogeneous,
then the 'M' is proportional to the volume inside the 'R', which varies as R3 .
So the acceleration is proportional to [ M / R2 ], in turn proportional to [ R3 / R2 ] = R.
Again, that's assuming the earth is homogeneous, which we know it isn't. But for a uniform,
homogeneous 'planet', the acceleration of gravity varies directly with the distance from the center.
What else can I help you with?
What are the Factors influencing acceleration due to gravity?
The factors influencing acceleration due to gravity are the mass of the object and the distance from the center of the Earth. Objects with more mass experience a stronger gravitational force, which leads to a higher acceleration due to gravity. Additionally, the acceleration due to gravity decreases as the distance between the object and the center of the Earth increases.
What happens to the acceleration due to gravity as you move farther away from the center of the earth?
The acceleration due to gravity decreases as you move farther away from the center of the Earth. This is because gravity weakens with distance according to the inverse-square law.
How much above the surface of earth does the acceleration due to gravity reduces by 36 percent of its value on the surface of earth radius of earth equals 6400 km?
The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.
How acceleration due to gravity value is calculated?
The acceleration of gravity due to a single object is(Universal gravitational constant) x (Mass of the object)/(distance from the object's center of mass)2
Are acceleration due to gravity on small stone and big stone equal?
Yes, the acceleration due to gravity on both small and big stones is equal because it depends only on the mass of the Earth and the distance from its center. The mass of the stone does not affect the acceleration due to gravity.
What are the Factors influencing acceleration due to gravity?
The factors influencing acceleration due to gravity are the mass of the object and the distance from the center of the Earth. Objects with more mass experience a stronger gravitational force, which leads to a higher acceleration due to gravity. Additionally, the acceleration due to gravity decreases as the distance between the object and the center of the Earth increases.
Why is acceleration due to gravity zero at the centre of the Earth?
Acceleration due to the earth's gravity is zero at the center of the Earth because at that point the mass of the earth is equally distributed in all directions, so pulling equally in all directions for a net zero pull. Simplistically, acceleration due to gravity decreases as distance from the center decreases. At the center the distance is zero, hence gravity is zero.
What happens to the acceleration due to gravity as you move farther away from the center of the earth?
The acceleration due to gravity decreases as you move farther away from the center of the Earth. This is because gravity weakens with distance according to the inverse-square law.
How does acceleration due to gravity changes with altitude?
The acceleration of gravity ... on or near the Earth, for example ... is inversely proportional to the square of the distance from the center of the Earth. So it diminishes as you rise from the surface. When you have ascended to an altitude of one Earth radius ... about 4,000 miles ... your distance from the center is then two Earth radii, so the acceleration of gravity has shrunk to 1/4 of its value on the surface.
How much above the surface of earth does the acceleration due to gravity reduces by 36 percent of its value on the surface of earth radius of earth equals 6400 km?
The acceleration due to gravity decreases with distance from the center of the Earth. Using the formula for gravitational acceleration (g) at a distance (r) from the center of the Earth: ( g' = \frac{G \cdot M}{(r+a)^2} ), where a is the radius of the Earth and G is the gravitational constant, you can calculate the distance above the surface of the Earth at which the acceleration due to gravity reduces by 36 percent.
How does the acceleration of gravity depend on it's distance from the center of the Earth?
acceleration due to gravity is given by, g=GM/R2 Hence distance from the earth increases g decreases and viceversa. So g at poles is greater than g at equator.
How acceleration due to gravity value is calculated?
The acceleration of gravity due to a single object is(Universal gravitational constant) x (Mass of the object)/(distance from the object's center of mass)2
Are acceleration due to gravity on small stone and big stone equal?
Yes, the acceleration due to gravity on both small and big stones is equal because it depends only on the mass of the Earth and the distance from its center. The mass of the stone does not affect the acceleration due to gravity.
Is earth's gravity the same on the surface as it is in the center of the earth?
No. At the centre of the earth the acceleration due to gravity is ZERO
The free fall acceleration of an object under earth's gravity is directed where?
The free fall acceleration of an object under Earth's gravity is directed downward, towards the center of the Earth. This acceleration is constant at approximately 9.81 m/s^2 on the surface of the Earth.
The value of acceleration due gravity at mountain?
Technically, the acceleration due to gravity is inversely proportional to the square of the distance from the center of the earth. That means that the farther from the earth's center you are, the smaller the acceleration due to gravity is. So gravitational acceleration is smaller on a mountain-top or in an airplane. Let's do a little calculation to get an idea of how much it changes. Let's figure out the acceleration of gravity inside an airplane at 35,000 ft above sea level: -- We know what it is at sea level on the equator: 9.78 meters per second2. That's when our distance from the center of the earth is equal to the earth's radius = 3,963 miles. -- When we're at 35,000 ft, we're farther from the center of the earth. 35,000 ft = (35,000 / 5280) = 6.63 miles. So our total distance from the center of the earth is (3,963 + 6.63) = 3,969.63 miles. -- The acceleration (and force) of gravity is inversely proportional to the square of this distance, so the new number is 9.78 times (3963 / 3969.63)2 = 9.78 x (0.9983298)2 = 9.78 x (0.996662) = 9.74736 m/s2 We have discovered that the acceleration due to gravity ... and the weight of every passenger in the airplane ... has become 0.33 percent smaller since they left the ground, because the distance from the center of the earth has increased. If you normally weigh 250 pounds on your bathroom scale, then at 35,000 ft, you weigh only 249.17 pounds.
How might Earth's gravity affect an object?
Earth's gravity affects an object by attracting it towards the center of the Earth, causing the object to have weight. The strength of this gravitational force depends on the mass of the object and the distance between the object and the center of the Earth. Objects experience a downward acceleration due to gravity, causing them to fall towards the Earth if unsupported.
