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The elastic potential energy (EEp) of the spring with displacement x from its original length is given by:

EEp = 1/2 kx2 (can be proved using integration)

where k is the spring constant of the spring.

So, if the displacement of the mass is doubled, the elastic EEp stored will increase by 22, that is by 4.

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13y ago
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7y ago

it goes up by four since energy is proportional to extension squared

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Q: How does the elastic potential energy in a mass spring system change if the displacement of the mass is doubled?
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