Well, first you solve for acceleration using "a= (Vf-Vi)/t"
a= (Vf-Vi)/t
a=(145-75)/15
a=70/15
a=14/3 m/s2
Then you can use "d=vit+1/2at2" to solve for distance
d=vit+1/2at2
d=(75)(15)+1/2(14/3)(15)2
d=1125 + 525
d=1650m
And there's your answer.
---- Alternatively, you could use d=t(vi+vf)/2
d=t(vi+vf)/2
d=15(75+145)/2
d=1650m
Acceleration= distance / velocity squared
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
To calculate velocity using acceleration, start by multiplying the acceleration by the change in time. For example, if the acceleration is 10 m/s2 and the change in time is 5 seconds, then there is a 50 m/s increase in velocity. Then, add the initial velocity to the increase in velocity.
Speed is the rate of motion usually expressed as distance traveled per unit of time.Velocity is the rate of change of position. Both speed and direction are required. Acceleration is the rate of change in velocity. In common speech, acceleration is only for an increase in speed; a decrease in speed is deceleration. In physics, any increase or decrease in speed or change of direction is referred to as acceleration. For more information, look at: http://en.wikipedia.org/wiki/Speed http://en.wikipedia.org/wiki/Velocity http://en.wikipedia.org/wiki/Acceleration
It is 0.1 metre per second-squared.
Acceleration occurs when velocity changes over time. The formula for it is as follows: a = (Vf - Vi) / t a: acceleration (meters/seconds2) Vf: Final velocity (meters/seconds) Vi: Initial Velocity (meters/seconds) t: Time (seconds)
Yes, velocity is acceleration x time. If acceleration is the same, velocity can be different as it changes with time. For example a car accelerating with constant acceleration will have a different velocity after 5 seconds than it will have at 2 seconds.
the acceleration is increasing speed Acceleration = velocity change / time velocity change = 0 to 25 mm/hr = 25 mm/hr time = 5 seconds therefore acceleration = 25/5 mm/hr per second = 5 mm per hour per second.
what is the change in speed or velocity? average acceleration will be change in speed or velocity divided by time taken (4 seconds in ur case)
Acceleration= distance / velocity squared
Since the derivative of velocity is acceleration, the answer would be technically 'no'. Here is why: v = 0 v' = 0 = a Or in variable form... v(x) = x v(0) = 0 v'(0) = 0 = a You can "trick" the derivative into saying that v'(x) = 1 = a (since the derivative of x = 1) and then stating v'(0) = 1 = a... but that is not entirely correct. Acceleration is a change over time and is measured at more then one point (i.e. the acceleration of this body of matter is y from time 1 to 5) unless using derivatives to form the equation of the acceleration line/curve. If an object has a constant acceleration of 1, then the velocity is constantly increasing over that time. Using the equation discussed above and looking at acceleration over time, at 0 seconds, acceleration is 0 and so is velocity, but from 0-1 seconds acceleration is 1 and velocity is 1 as well. 0-2 seconds, acceleration is 1, but velocity would be 2 (at the end of 2 seconds).
If velocity is steady and doesn't change, then there is 0 acceleration.
That depends on its initial velocity and its acceleration. V1 = V0 + a * t
Acceleration is the time rate of change of velocity. If velocity is constant, then acceleration is zero. Note: "100 km per h for 10 seconds" is a constant speed, but not necessarily a constant velocity, since we're told nothing about the direction. If the car moves in a perfectly straight line during those 10 seconds, then its velocity is constant. If it makes a curve, then its velocity is not constant even though its speed is, and there is acceleration.
To calculate velocity using acceleration, start by multiplying the acceleration by the change in time. For example, if the acceleration is 10 m/s2 and the change in time is 5 seconds, then there is a 50 m/s increase in velocity. Then, add the initial velocity to the increase in velocity.
The answer will depend on its acceleration.
To calculate the acceleration, you need to divide the net force by the mass.