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Well, first you solve for acceleration using "a= (Vf-Vi)/t"

a= (Vf-Vi)/t

a=(145-75)/15

a=70/15

a=14/3 m/s2

Then you can use "d=vit+1/2at2" to solve for distance

d=vit+1/2at2

d=(75)(15)+1/2(14/3)(15)2

d=1125 + 525

d=1650m

And there's your answer.

---- Alternatively, you could use d=t(vi+vf)/2

d=t(vi+vf)/2

d=15(75+145)/2

d=1650m

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Q: How fardoes a plane fly in 15 seconds while its velocity is increasing from 75ms to 145ms at a uniform rate of acceleration?
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