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Let us assume that you have a "very long" tube filled with pure water and manage to invert the tube (open-end down) into a "very large" water container, without losing any water in the tube (no air has entered the tube). We shall see how long the tube will be in order to form a "vacuum."
At this point (at sea level), the water inside the tube exerts a downward pressure on the water outside the tube. The water level will settle, in time, so that the downward pressure exerted by the tube water is equal to the atmospheric pressure at the water level outside the tube. If the pressure is not equal, then the water level has not settled yet.
Water pressure exerted = height of the water column [m] * density [kg/m^3] * g [m/s^2] = h [m] * 1000 [kg / m^3] * 9.8 [m/s^2] ~ 10,000 [kg / m^2 / s^2] *h [m] = 10000 * h [N/m^2]
Atmospheric pressure at sea level (say at 20C) ~ 100 [kPa] = 100,000 [N/m^2]
Hence, 10000 * h ~ 100000, or h ~ 10 [m].
At room temperature and sea level, the "vacuum" can support ~ 10 meter of water. The aforementioned tube has to be at least that tall in order for a "vacuum" to form.
P.S. You need to use more precise values in the calculation. The "vacuum" is not really a void -- it is saturated with water vapor.
Wiki User
∙ 14y ago
Wiki User
∙ 16y agoJust short of 10 meters.....no matter what. Wells deeper than this MUST have the pump at the bottom of the hole. They don't depend on vacuum to lift the water.
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What capacity of pump to be used to lift water at a height of 10 mtr?
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