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Let us assume that you have a "very long" tube filled with pure water and manage to invert the tube (open-end down) into a "very large" water container, without losing any water in the tube (no air has entered the tube). We shall see how long the tube will be in order to form a "vacuum."
At this point (at sea level), the water inside the tube exerts a downward pressure on the water outside the tube. The water level will settle, in time, so that the downward pressure exerted by the tube water is equal to the atmospheric pressure at the water level outside the tube. If the pressure is not equal, then the water level has not settled yet.
Water pressure exerted = height of the water column [m] * density [kg/m^3] * g [m/s^2] = h [m] * 1000 [kg / m^3] * 9.8 [m/s^2] ~ 10,000 [kg / m^2 / s^2] *h [m] = 10000 * h [N/m^2]
Atmospheric pressure at sea level (say at 20C) ~ 100 [kPa] = 100,000 [N/m^2]
Hence, 10000 * h ~ 100000, or h ~ 10 [m].
At room temperature and sea level, the "vacuum" can support ~ 10 meter of water. The aforementioned tube has to be at least that tall in order for a "vacuum" to form.
P.S. You need to use more precise values in the calculation. The "vacuum" is not really a void -- it is saturated with water vapor.
What else can I help you with?
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How much vacuum pressure would be needed to allow salt water to rise up a tube of 6inch diameter to a height of 100 feet.?
first i cant solve this because i don't have (X Saltwater and X type of vacuum+ Pressure of it) but i do have the right idea.. 1: Find the greatest amount of force that the vacuum can lift or the psi. 2: figure out the amount and the weight of salt water you want to lift 3: figure out if the vacuum can even have enough lift with a 6in tube 4: make sure all the tubes are sealed good 5: test it out.. Hope that helps! And Happy testing! :]
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What simple machine is a shadoof?
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