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How long does it take a car to travel 30m if it accelerates from rest at a rate of 2m sec?
15sec
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The question is incorrect and so got a wrong answer. Acceleration cannot be measured in m sec but m sec-2. The previous answerer, assumed that the questioner had meant velocity, not acceleration. If the velocity had been 2 m sec-1 then the time would have been 15 seconds. But it was not even m sec-1! It seemed the units were wrong.
If you assume that acceleration = 2 m sec-2 then
t2 = 2s/a = 2*30/2 = 30
and so
t = sqrt(30) seconds = 5.48 seconds (approx)
What else can I help you with?
How far does a car travel when it starts from rest and accelerates to a certain speed?
The distance a car travels when it starts from rest and accelerates to a certain speed depends on the acceleration of the car and the time it takes to reach that speed. The formula to calculate this distance is d 0.5 a t2, where d is the distance, a is the acceleration, and t is the time taken to reach the speed.
The ë v is the same as the ending velocity when the object starts from?
The ë v is the same as the ending velocity when the object starts from rest and accelerates at a constant rate for a certain amount of time before reaching that velocity.
A car accelerates uniformly from rest at a rate of plus 10ms2 How far will the car travel in 4s?
The distance traveled by the car can be calculated using the equation (s = \frac{1}{2}at^2), where (s) is the distance, (a) is the acceleration, and (t) is the time. Plugging in the values, we have (s = \frac{1}{2} \times 10 \times (4)^2 = 80) meters. Therefore, the car will travel 80 meters in 4 seconds.
Sydney has a car that accelerates at 5.9ms squared. She was races Sean. Both start from rest but Sean starts 1.0 seconds early. Seans car accelerates at 3.6ms squared.?
Sydney's car accelerates at 5.9 m/s^2, while Sean's car accelerates at 3.6 m/s^2. Sean starting 1.0 second early gives him an initial distance advantage, but Sydney's higher acceleration rate means she will catch up and overtake Sean at some point during the race. The exact point of overtaking can be calculated by comparing their positions over time.
What Does free fall from the rest mean?
Free fall from rest typically refers to an object falling under the influence of gravity without any initial velocity. This means that the object starts falling from a stationary position and solely accelerates due to gravity without any other forces acting on it. Objects in free fall from rest will accelerate at a rate of approximately 9.81 m/s^2 on Earth.
How long does a car take to travel 30m if it accelerates from rest at a rate of 2 meter per second square?
sqrt(30) seconds = 5.48 seconds (approx)
How many meters does a car travel that starts from rest and accelerates for 4.7 seconds with an acceleration rate of 3.6 meters per second squared?
60.912 meters in that time
A race car accelerates from rest at a rate of 6 ms How fast will the car be going after 5 seconds?
30m/s
A race car starts from rest and accelerates uniformly to a speed of 40 ms in 8.0 seconds how far will the car travel during the 8 seconds?
160 m
How far does a car travel when it starts from rest and accelerates to a certain speed?
The distance a car travels when it starts from rest and accelerates to a certain speed depends on the acceleration of the car and the time it takes to reach that speed. The formula to calculate this distance is d 0.5 a t2, where d is the distance, a is the acceleration, and t is the time taken to reach the speed.
The ë v is the same as the ending velocity when the object starts from?
The ë v is the same as the ending velocity when the object starts from rest and accelerates at a constant rate for a certain amount of time before reaching that velocity.
A car accelerates from rest and accelerates at 3 ms-2 how long it will take to reach a velocity of 30ms-1?
Acceleration = (change in speed) / (time for the change)3 = (30) / (time)3 x (time) = 30time = 30/3 = 10 seconds
What is the effect of force on bodies at rest?
The force accelerates the body, a=F/m.
A car accelerates uniformly from rest at a rate of plus 10ms2 How far will the car travel in 4s?
The distance traveled by the car can be calculated using the equation (s = \frac{1}{2}at^2), where (s) is the distance, (a) is the acceleration, and (t) is the time. Plugging in the values, we have (s = \frac{1}{2} \times 10 \times (4)^2 = 80) meters. Therefore, the car will travel 80 meters in 4 seconds.
When a moving bumper car collides with a bumper car at rest what will occur?
The second car accelerates
How pluse rate change at rest?
How pluse rate change at rest?
A race car starting from rest accelerates uniformly at a rate of 4.90 meters per second what is the cars speed after it has traveled 200 meters?
Acceleration cannot be measured in metres per second. There is, therefore a fundamental problem with the question.
