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How long will it take a shell fired from a cliff at an inital velocity of 800ms at an angle of 30 below the horizontal to reach the ground 150m below?
Wiki User
∙ 11y ago
H = H0 + V0T + 1/2 G T2
H0 = 150 m
V0 = -800 sin(30) = -400 m/s
G = -9.8 m/s2
We want 'T' when H=0 .
0 = 150 - 400 T - 4.9 T2
T = [ 400 ± sqrt(160,000 + 2,940) ] / -9.8
T = -82.01 sec
T = 0.3733 sec
The physically meaningful root is
T = 0.3733 seconds (rounded)
Wiki User
∙ 11y ago
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A 5g bullet is fired from a 500g if the bullet leaves the gun going 800ms with what speed does it recoil?
The idea is to use conservation of momentum. The momentum before the shot is fired is assumed to be zero, so write an equation that states that the momentum after the shot is zero, and solve it. The total momentum, of course, is the sum of the momentum of the two parts; for each part, the momentum is mass x velocity.
A 5 g bullet is fired from a 5000g gun If the bullet leaves the gun going 800MS with what speed does the gun recoil?
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1
Can you play online on battlefield 3 without the online pass?
nope. EA isn't that generous. you either need to buy the game new or spend 800ms points (about 10$) to buy the pass.
A 5g bullet is fired from a 500g if the bullet leaves the gun going 800ms with what speed does it recoil?
The idea is to use conservation of momentum. The momentum before the shot is fired is assumed to be zero, so write an equation that states that the momentum after the shot is zero, and solve it. The total momentum, of course, is the sum of the momentum of the two parts; for each part, the momentum is mass x velocity.
A 5 g bullet is fired from a 5000g gun If the bullet leaves the gun going 800MS with what speed does the gun recoil?
Speed of recoil of the gun = change in momentum/mass of the bullet = 5 x 10-3 x 800/5 msec-1 = 0.8 msec-1
How can you buy halo reach noble map pack?
well there are 2 ways but first you need xbox live the first way is you go to xbox live market place then you go on the search go on the letter H and look for halo reach go to the side when you find it and look for noble map pack and click download if you have no Microsoft points buy some of the xbox buy 800 Microsoft points then click download (you will need to enter your credit card number) the 2nd way is go to the shop and go buy 800 Microsoft points then go home scrub the code of go on redeem code and type the code in you will get your points go to xbox live marketplace then download it and you wont be intrested in noble map pack because in march there making defiant map pack for 800MS hope this helped
Calculate the time required to dial the number 009144414630 using a rotary dial telephone if subscriber takes 600ms on an average to rotate the dial for a single digit and interdigit gap is 200ms.?
if you add 600ms+200ms =800ms each number x 12 =9.6 seconds====================================================I disagree. The answer is the sum of the time that takes in the total dialing spaces. So, in 0 there are 10 spaces; in 9 - are 9, etc.(10 + 10 + 9 + 1 + 4 + 4 + 4 + 1 + 4 + 6 + 3 + 10 ) x 600 ms = 13200ms = 13.2 seconds. [??? 66 x 600 = 39600ms = 39.6 seconds]AnswerFor every digit for ex. 009144414630 the ave. single digit is 600 ms so we count the no. of digits of the telephone number.. in this example the total # of digits is 12. Use the formula:Time= [(n x T) + ((n-1)x t)]where: n= no. of digitsT= single digit timet= interdigit gap timeif you want to know its 9400ms or 94 sec[??? 9400 ms = 9.4 seconds]Alternative:I would take the problem to mean:Once the dialer has chosen the digit to be dialed and has dialed it (cocked it), the mechanism requires 600 ms per increment to actually register the digit and return to the ready state to accept another digit. That is to say; it takes the dialer 200 ms to chose and "cock" a specific digit into the rotor and 600 ms per increment for the rotor to "count it off", returning to the ready state. A "1" takes 600 ms to register, "2" takes 1200 ms and so on to the "0" which takes 6000 ms to complete.(6000 ms = 6 seconds and I am sure that the old rotary phones were not that slow. Therefore, I suspect that the author added a zero and the 600 ms is really only 60 ms which gives a time of 0.6 seconds for the "0" to complete. However, by the same token, 200 ms or 1/5-second does not seem to be excessive for choosing and "cocking" a digit so I will stick with that figure in the following.)From the word "Go", the dialer must chose and cock each digit of the number to be dialed.# of digits to be dialed = 12Dialer time = 12 x 200 ms = 2400 ms# of dialing increments = 10+10+9+1+4+4+4+1+4+3+6+10 = 66Rotor time = 66 x 60 ms = 3960 ms (39600 ms @ 600 ms)Total time = 6360 ms = 6.36 seconds (42 seconds @ 600 ms)This question has created a mess. Other sources put the pulse rate of rotary phones @ 10 pps to 20 pps and that would seem to indicate 1 to 0.5 seconds to tap out 10 pulses, a far cry from the 6 seconds indicated by the 600 ms rate given in the original question.Buddika:I think it should be in following waystep 1: Average time to dial 12 digits 12 * 600ms=7.2 sstep 2: if pulse rate is 10 pulse/sec and 10% tolerancepulse time=(10+10+9+1+4+4+4+1+4+6+3+10)/10= 6.6stolerance = +_6.6 10%=+_0.66sMean tolerance=0.66/2=0.33sTotal pulse time=6.93sstep 3: Total inter-digit gap=11*200ms=2.2sSo total time=7.2+6.93+2.2=16.33s(but book says its 16.44s)
