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To calculate the heat required to raise the temperature of water, you can use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature. For 5 pounds of water, you'd convert that to approximately 2268 grams. The specific heat capacity of water is 4.186 J/g°C. Considering the conversion factor for BTU to J (1 BTU = 1055.06 J), you'd then convert the result to BTU, which comes out to approximately 1.53 BTU.
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How much heat from 5 pounds of 232 degrees steam to create 5 pounds of 162 degrees of water?
To calculate the heat required to cool steam to water at a lower temperature, you can use the formula: Q = mcΔT Where: Q = heat energy m = mass c = specific heat capacity ΔT = change in temperature Given: m = 5 pounds ΔT = (232 - 162) = 70 degrees F Specific heat capacity of water = 1 cal/g°C Convert pounds to grams: 1 pound ≈ 453.592 grams Now, plug in the values into the formula to calculate the heat energy.
How much joules does it take to heat water to 100 degrees?
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
How much energy is needed to change 125g of ice at -32.9 degrees to water at 75 degrees?
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
How much heat is required to raise the temperature of 0.25 kg of water from 20 Celsius to 30 Celsius?
The specific heat capacity of water is 4186 J/kg*C. To calculate the heat required, use the formula: heat = mass * specific heat capacity * change in temperature. Plugging in the values, the heat required to raise the temperature of 0.25 kg of water by 10 degrees Celsius is approximately 1046.5 Joules.
How many BTU will it take to change 10 pounds of ice at 20 degrees to steam at 220 degrees?
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
How much heat from 5 pounds of 232 degrees steam to create 5 pounds of 162 degrees of water?
To calculate the heat required to cool steam to water at a lower temperature, you can use the formula: Q = mcΔT Where: Q = heat energy m = mass c = specific heat capacity ΔT = change in temperature Given: m = 5 pounds ΔT = (232 - 162) = 70 degrees F Specific heat capacity of water = 1 cal/g°C Convert pounds to grams: 1 pound ≈ 453.592 grams Now, plug in the values into the formula to calculate the heat energy.
How many pounds of steam are required to heat one gallon of water?
it takes 2 pounds of it
How much heat is required to change 0.2kg of ice at -5 degrees to water at 5 degrees?
Heat required for this transition is given as the the sum of three heatsheat required for heating the ice from -5 degree Celsius +latent heat(conversion of ice at zero degree to water at zero degrees)+heat required to heat the water from 0 to 5 degree CelsiusHeating of ice=m x s x delta T,where m is the mass ,s is the specific heat of ice=200x0.5x5=500calmelting of ice=mxlatent heat=200x80=16,000calHeating of water=m x s x delta T,where m is the mass ,s is the specific heat of water =200x1x5=1000calTotal heat required=500+16,000+1000=17,500 cal
How much joules does it take to heat water to 100 degrees?
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
How much energy is needed to change 125g of ice at -32.9 degrees to water at 75 degrees?
To calculate the energy needed to change ice at -32.9 degrees to water at 75 degrees, you need to consider the energy required for three steps: Heating ice from -32.9 degrees to 0 degrees (specific heat capacity of ice) Melting ice at 0 degrees into water at 0 degrees (latent heat of fusion of ice) Heating water from 0 degrees to 75 degrees (specific heat capacity of water) Once you have the energy needed for each step, you can add them together to find the total energy required.
How long would it take to heat 200 gallons of water 180 degrees if the water was 50 degrees and you only had 600 Btu water heater?
To calculate the time it would take to heat 200 gallons of water by 180 degrees using a 600 Btu water heater, you would first determine the total heat required: Calculate the heat energy required: Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the temperature change. Then, calculate the time required to heat the water using the formula: Time = Q / power of the heater. These calculations will give you an estimate of the time needed to heat the water based on the specific heat capacity of water and the power of the heater.
How much heat in joules is required to convert 92g of ice at 0.00 degrees Celsius to water vapor at 148 degrees Celsius?
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How much energy is required to raise 160 cfm of air from 10 to 170 degrees f?
The amount of energy that is required to 160 cfm of air from 10 to 170 degrees F is 200 btu. T he formula is weight x specific heat x temperature difference so we have10 pounds x 1.00 x 2010 for 10 pounds of water.
How much heat is required to evaporate 1 liter of water at 100 degree celsius?
The heat required to evaporate 1 liter of water at 100 degrees Celsius is known as the latent heat of vaporization of water, which is approximately 2260 kJ/kg. Since the density of water is about 1000 kg/m³, the heat required would be around 2260 kJ.
How much heat is required to raise the temperature of 0.25 kg of water from 20 Celsius to 30 Celsius?
The specific heat capacity of water is 4186 J/kg*C. To calculate the heat required, use the formula: heat = mass * specific heat capacity * change in temperature. Plugging in the values, the heat required to raise the temperature of 0.25 kg of water by 10 degrees Celsius is approximately 1046.5 Joules.
How many Btu are required to change 600 pounds of water at 75 degrees F to steam at 212 degrees F?
1 BTU is required to raise 1lb of water 1 degree F in 1 hour. 212-75=137 degrees 600 lbs water x 137 degrees= 82,200 BTU's required to change 75 degree water to 212 degree water. To change 212 degree water to 212 degree steam it requires 970 btu's (latent heat of vaporization) per lb of water 970 btu x 600 lbs water = 582,000 btu Answer - 582,000 btu+ 82,200 btu = 664,200 btu's
How many BTU will it take to change 10 pounds of ice at 20 degrees to steam at 220 degrees?
To change 10 pounds of ice at 20 degrees Fahrenheit to steam at 220 degrees Fahrenheit, you need to supply enough energy to first melt the ice, then heat the water to the boiling point, and finally convert it to steam. This process requires approximately 180 BTUs per pound of ice to melt it, 180 BTUs per pound of water to heat it to the boiling point, and then 970 BTUs per pound of water to convert it to steam. So, for 10 pounds of ice, the total BTUs required would be around 18,300 BTUs.
