1x10^5 Pa (100,000 Pa)
Pa :- Pascal
To raise water 1 meter, you would need to exert a pressure equivalent to the weight of the water column above. For water, the pressure increase with depth is 9.81 kPa per meter. Therefore, to raise water 1 meter, you would need to apply a pressure of 9.81 kPa.
The pressure at 20 meters below sea level is approximately 3 atmospheres, which is equivalent to about 2,942 millibars or 294.2 kPa. This pressure is due to the weight of the water above exerting force on the area at that depth.
783,0 mm Hg is equal to 104,3914 kPa.
The gauge pressure is the absolute pressure minus atmospheric pressure. If atmospheric pressure is considered to be 101 kPa, then the gauge pressure would be 219 kPa.
424 kPa is 61.5 pounds per square inch (psi).
Three times atmospheric pressure is equivalent to approximately 3 x 101.3 kPa, which equals about 303.9 kPa. Since pressure increases by about 1 atmosphere (101.3 kPa) for every 10 meters of water depth, three times atmospheric pressure occurs at a depth of roughly 30 meters (or about 98 feet) underwater.
The vapor pressure of water at 70 degrees Celsius is approximately 23.76 kPa. To find the partial pressure of water vapor in the mixture, subtract this vapor pressure from the total pressure of 89.9 kPa. Therefore, the partial pressure of water vapor would be 89.9 kPa - 23.76 kPa = 66.14 kPa.
120 kP
The absolute pressure at 20 meters underwater can be calculated using the formula: ( P = P_{atm} + \rho g h ), where ( P_{atm} ) is the atmospheric pressure at sea level (approximately 101.3 kPa), ( \rho ) is the density of water (around 1000 kg/m³), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( h ) is the depth in meters. At 20 meters, the pressure due to the water column is about 196.2 kPa (1000 kg/m³ × 9.81 m/s² × 20 m). Adding atmospheric pressure, the total absolute pressure is approximately 297.5 kPa.
To raise water 1 meter, you would need to exert a pressure equivalent to the weight of the water column above. For water, the pressure increase with depth is 9.81 kPa per meter. Therefore, to raise water 1 meter, you would need to apply a pressure of 9.81 kPa.
== == Height (m) x Gravity (m/s2) = Pressure (kPa) Gravity is 9.81m/s2 at sea level, so an easy approximation is: 1 metre of head = 10kPa
At a depth of 3,000 meters below water level, the pressure can be calculated using the formula: pressure = depth × density of water × gravitational acceleration. The average density of seawater is about 1,025 kg/m³, and gravitational acceleration is approximately 9.81 m/s². Thus, the pressure at this depth is roughly 30,000 kPa, or about 300 times atmospheric pressure (1 atm being approximately 101.3 kPa).
kPa is pressure, how much area is the pressure acting on
The absolute pressure can be calculated by adding the atmospheric pressure to the gauge pressure. If the atmospheric pressure is 101.3 kPa, then the absolute pressure of the gas would be 206 kPa + 101.3 kPa = 307.3 kPa.
Using Boyle's Law, we can calculate the new volume by dividing the initial pressure by the final pressure and multiplying it by the initial volume. New Volume = (Initial Pressure / Final Pressure) * Initial Volume = (200 kPa / 400 kPa) * 50 cubic meters = 25 cubic meters.
Your question is not clear. Static pressure in metres head converts to kilopascals: one metre of head is 10 kPa, 10 m is 100 kPa, and so on.
The pressure at 20 meters below sea level is approximately 3 atmospheres, which is equivalent to about 2,942 millibars or 294.2 kPa. This pressure is due to the weight of the water above exerting force on the area at that depth.