A 60 watt light bulb typically draws 0.5 amps from a 120-volt power source. This is calculated by dividing the wattage (60 watts) by the voltage (120 volts).
On this calculation I am assuming that the light bulb is using a 120 volt source. Watts = Amps x Volts. Amps = Watts/Volts, 40/120 = .33 amps. R = Volts/Amps, 120/.33 = 363.6 ohms resistance in the 40 watt light bulb.
A 150-watt light bulb typically produces around 2600-2800 lumens.
Yes, a 100-watt light bulb is brighter than a 60-watt light bulb because it produces more light.
No, James Watt did not invent the light bulb. The light bulb was invented by Thomas Edison in 1879. James Watt was known for his improvements to the steam engine.
The main difference between a 100-watt and a 75-watt light bulb is the amount of light output they produce. A 100-watt bulb will be brighter and consume more energy compared to a 75-watt bulb. The 100-watt bulb may also generate more heat than the 75-watt bulb.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
Each 32-watt bulb in a 48-inch fluorescent light typically draws around 0.27 amps. Therefore, a two-bulb setup would draw approximately 0.54 amps in total.
A 65 Watt incandescent light bulb should draw 65W/120V = 541.67mA
A 120 volt table lamp with a 75 watt bulb will pull 0.625 amps. With a 100 watt bulb it will pull 0.833 amps. And with a modern fluorescent 13 watt bulb it will pull 0.108 amps.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
A 60 watt bulb at 12 volts will pull 5 amps of current.
Amps x volts = watts So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
To find the current in amps for a 50-watt light bulb, you can use the formula ( I = \frac{P}{V} ), where ( I ) is the current in amps, ( P ) is the power in watts, and ( V ) is the voltage in volts. For example, if the bulb operates at 120 volts, the current would be ( \frac{50}{120} ), which equals approximately 0.42 amps. If the bulb operates at a different voltage, simply adjust the voltage in the formula accordingly.
To calculate the amperage of a 40-watt bulb, you need to use the formula: Amps = Watts / Volts. If the bulb operates at 120 volts (standard for US households), the amperage will be 0.33 amps (40 watts / 120 volts).
It is drawing .06 amps.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
Thomas Edison invented the vacuum sealed filiment light bulb. James Watt coined the term "watt" as the work done by an electrical circuit, which can be calculated as Volts multiplied by Amps.