How many gallons of water per foot will a 24 inch pipe hold?

Answer 1

I will work with the assumption that you mean an 18 inch diameter pipe.

The radius (r) is 9 inches and the length (l) is 12 inches per foot.

The volume contained will be calculated by ∏r2l = ∏ x 92 x 12.

If we use 3.1416 as the value of ∏, that gives us 3.1416 x 81 x 12, which works out at 3,053.6352 cubic inches of water.

Now, an Imperial gallon and a US gallon are different - an Imperial gallon holds 277.42 cubic inches and a US gallon holds 231 cubic inches

So in Imperial gallons the 12 inches of pipe holds 3,053.6352 / 277.42 = 11.0072 gallons

and in US gallons it holds 3,053.6352 / 231 = 13.2192 gallons.

Answer 2

231 cubic inches = 1 gallon

Volume of a cylinder = (pi) (Radius)2 (length)

Radius of an 18-inch pipe = 9 inches.

Volume = (pi) (9)2 (40) = 10,178.76 cubic inches = 44.06 gallons (rounded)

That's the volume of the pipe. I have no way of knowing how much water is

in it. It may even be empty, and you may be pulling a fast one.

Answer 3

An 18-inch pipe one mile long holds 69,797 gallons of water. This equates to 9,330.5 cubic feet.

Answer 4

A pipe with a diameter of 2 4 inches will hold 19.6 Imperial gallons per foot.

Answer 5

A 24 inch pipe has a cross-sectional area of 4.57 square feet. If you assume the pipe is a cylinder, it will hold approximately 34.15 gallons of water per foot.