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I will work with the assumption that you mean an 18 inch diameter pipe.
The radius (r) is 9 inches and the length (l) is 12 inches per foot.
The volume contained will be calculated by ∏r2l = ∏ x 92 x 12.
If we use 3.1416 as the value of ∏, that gives us 3.1416 x 81 x 12, which works out at 3,053.6352 cubic inches of water.
Now, an Imperial gallon and a US gallon are different - an Imperial gallon holds 277.42 cubic inches and a US gallon holds 231 cubic inches
So in Imperial gallons the 12 inches of pipe holds 3,053.6352 / 277.42 = 11.0072 gallons
and in US gallons it holds 3,053.6352 / 231 = 13.2192 gallons.
Wiki User
∙ 15y ago
Wiki User
∙ 12y ago231 cubic inches = 1 gallon
Volume of a cylinder = (pi) (Radius)2 (length)
Radius of an 18-inch pipe = 9 inches.
Volume = (pi) (9)2 (40) = 10,178.76 cubic inches = 44.06 gallons (rounded)
That's the volume of the pipe. I have no way of knowing how much water is
in it. It may even be empty, and you may be pulling a fast one.
Wiki User
∙ 9y agoAn 18-inch pipe one mile long holds 69,797 gallons of water. This equates to 9,330.5 cubic feet.
Wiki User
∙ 7y agoA pipe with a diameter of 2 4 inches will hold 19.6 Imperial gallons per foot.
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