To calculate the grams of steam formed, you need to know the amount of water being converted to steam and the conditions under which the water is being vaporized (e.g., temperature, pressure). This information is essential in using the heat of vaporization to determine the amount of energy needed to convert the water to steam, and subsequently the mass of steam produced.
To calculate the grams of ice formed from 100 grams of steam, we need to consider the heat exchange involved in the phase changes. First, the steam needs to lose heat to condense into water, then cool further to freeze into ice. Given the specific heat capacities and enthalpies of fusion/vaporization of water, you can determine the final mass of ice formed.
The mass would be approx 39 grams: the volume depends on the pressure and also the temperature.
It depends on how big the steam is. If the steam is as small as water vapour, it cannot be seen by the naked eye. If the steam is as big as water droplets, it can be seen by naked eye. But if many steam, it always can be seen by naked eye.
To make 37000 pounds of steam, you would need 37000 pounds of water. This is because steam is simply water in the gas phase, so the weight of the steam would be equal to the weight of the water used to generate it.
It takes approximately 970 BTUs to convert one pound of water at 212°F (100°C) to steam at the same temperature.
To calculate the grams of ice formed from 100 grams of steam, we need to consider the heat exchange involved in the phase changes. First, the steam needs to lose heat to condense into water, then cool further to freeze into ice. Given the specific heat capacities and enthalpies of fusion/vaporization of water, you can determine the final mass of ice formed.
25
if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
The mass of water is 5,4 g.
25 grams of steam are in 25 grams of water.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
To determine the grams of sulfur formed, we need to first identify the balanced chemical equation for the reaction involving sulfur. Once we have the balanced equation, we can use stoichiometry to determine the mass of sulfur formed using the given value of water formed.
To determine the number of grams of water formed, we need to calculate the moles of butanol (C4H9OH) and then use the balanced chemical equation to find the moles of water produced in the combustion reaction. From there, we convert moles of water to grams. The balanced equation for the combustion of butanol is C4H9OH + 6O2 → 4CO2 + 5H2O.
32 grams of water
5 grams of water in a teaspoon
5 grams of water in a teaspoon