It depends on the weight and length of the iron rods. On average, a standard 1-inch diameter iron rod that is 20 feet long weighs around 13.5 pounds (6.12 kg). Therefore, it would take approximately 146 iron rods to make a ton (2,000 pounds or 907 kg).
The number of steel rods in a ton will depend on the size and diameter of the rods. Typically, a ton of steel rods can range from around 540 to 650 rods, assuming they are standard size and weight.
No, a ton of feathers and a ton of iron have the same weight because they both weigh a ton. However, the volume occupied by the ton of feathers would be significantly larger than the ton of iron due to the lower density of feathers.
There are 1000 kilograms in a ton.
The volume of a ton of iron can vary depending on the density of the iron. On average, the density of iron is approximately 7.87 grams per cubic centimeter. Therefore, a ton (2000 pounds) of iron would have a volume of around 254,000 cubic centimeters or 254 liters.
The number of drums that make up a ton depends on the size and weight of each drum. Generally, you would need to know the weight of one drum in order to calculate how many drums make up a ton.
The number of steel rods in a ton will depend on the size and diameter of the rods. Typically, a ton of steel rods can range from around 540 to 650 rods, assuming they are standard size and weight.
269 6M lenths
It is a "lump" of iron with a mass of one metric ton.
Iron is about a hundred dollars a ton.
No, a ton of feathers and a ton of iron have the same weight because they both weigh a ton. However, the volume occupied by the ton of feathers would be significantly larger than the ton of iron due to the lower density of feathers.
1.5
Around 100$ per ton.
Around 100$ per ton.
it takes 1.8 million ounces in a ton
There are 1000 kilograms in a ton.
2240 pounds = 1 Imperial ton
It takes two thousand pounds of feathers to make one ton. Depending on the size of the birds from which the feathers are gathered from would determine how many feathers would make a ton.