To calculate the number of kilocalories required to heat something up, you need to know the specific heat capacity of the substance. The specific heat capacity of water is 1 calorie/gram°C. The formula to calculate the heat energy required is Q = mcΔT, where Q is the heat energy, m is the mass of the substance, c is the specific heat capacity, and ΔT is the change in temperature.
To convert kilojoules (kJ) to kilocalories, you can use the conversion factor of 1 kJ is equivalent to 0.239 kcal. So, 240 kJ is equal to 240 x 0.239 ≈ 57.4 kilocalories of heat.
To heat 1 gram of water by 1 degree Celsius, it takes 1 calorie. Therefore, to heat water from 65 oF to 105 oF, you would need 40 calories per gram of water. If you are working in kilocalories, this would be equivalent to 0.04 kilocalories.
Heat flow is typically measured in units of watts (W) or joules per second (J/s).
To convert kilocalories per hour to watts, divide by 860: 100 kilocalories per hour / 860 = 0.1163 watts. So, the college student's rate of energy production is approximately 0.1163 watts.
It could be either; but when you are talking about food, what is of interest is usually the energy content - meaning, chemical energy stored in the food. Heat IS energy, and a kilocalorie is the energy required to heat one kilogram of water by one degree Celsius.
Oxygen and heat to get things going
To convert kilojoules (kJ) to kilocalories, you can use the conversion factor of 1 kJ is equivalent to 0.239 kcal. So, 240 kJ is equal to 240 x 0.239 ≈ 57.4 kilocalories of heat.
To heat 1 gram of water by 1 degree Celsius, it takes 1 calorie. Therefore, to heat water from 65 oF to 105 oF, you would need 40 calories per gram of water. If you are working in kilocalories, this would be equivalent to 0.04 kilocalories.
This heat is 32,48 joules.
The specific heat capacity of aluminum is 0.897 J/g°C. To convert this to kcal/g°C, we divide by 4.184 to get 0.214 kcal/g°C. Therefore, the total kilocalories of heat required to raise the temperature of 225g of aluminum from 20°C would be 225g * 20°C * 0.214 kcal/g°C = 966 kcal.
Heat flow is typically measured in units of watts (W) or joules per second (J/s).
Kilo means 1,000, so kilocalories means a thousand calories.
To convert kilocalories per hour to watts, divide by 860: 100 kilocalories per hour / 860 = 0.1163 watts. So, the college student's rate of energy production is approximately 0.1163 watts.
The specific heat capacity of water is 1 calorie/gram °C. To convert this to kilocalories, we divide by 1000, so 1kcal/kg°C. The temperature change is 45 - 13 = 32°C. Therefore, the heat required is 460g * 32°C * 1kcal/kg°C = 14720 kcal.
The specific heat capacity of water is 4.18 J/g°C. First, convert 160g to 0.16kg. Then, use the formula: Q = m * c * ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plug in the values and convert the result to kilocalories.
It could be either; but when you are talking about food, what is of interest is usually the energy content - meaning, chemical energy stored in the food. Heat IS energy, and a kilocalorie is the energy required to heat one kilogram of water by one degree Celsius.
The heat produced by a 1200-W hair dryer can be converted to kilocalories by multiplying the power in watts by the conversion factor of 0.001 kcal/s per watt. Therefore, 1200 W hair dryer would produce 1.2 kilocalories of heat each second.