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The only information you've given is you want to know moles and how many Liters there are. To calculate, you need to know what you are preparing(i.e., N2, AgNO3, etc.), and it's Molarity(M).

Here's an example:

How many moles of silver nitrate are needed to prepare 250mL of standard 0.100M silver nitrate solution?

Note: M = moles of solute(stuff) / volume of solution(L) = # moles / L

So, ?/250mL=.1M

First we use dimensional analysis to convert mL to L.

250mL x 10-3 L / 1 mL = .25L

Since we know M=moles/L, we can take the Molarity and put it in moles/L form.

.10M = .10 mol/L

Finally,

.10 mol/L x .25L = .025 mol AgNO3

We can make a general assumption for your question and say the M is standard .100M.

.10M = .10 mol/L

.10 mol/L x 48L = 4.8 moles

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13y ago

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