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A 60cm pendulum will make 53 swings in one minute. The formula to calculate this is: number of swings = (60 / 1.18) * 60.

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How many shovels of sand in a yard of material?

It depends on the size of the shovel and the density of the sand. On average, a standard shovel can hold about 0.5 cubic feet of material. A yard is equivalent to 27 cubic feet, so roughly 54 shovels may be needed to move a yard of sand.


Torque A meter stick weighs 200N and is supported at the centerThree weighs of 100N 150N and 300N are placed respectively at the 10cm 40cm and 60cm points of the meter stick Where should another?

Your set-up is so long that that you ran out of space before you could ask thequestion. In fact, you got cut off leaving us with two questions . . . howheavy should a single weight be, and where should it hang, in order to balancethe whole thing ?I just noticed that since the stick is 1 meter long, and the three originalweights are placed at the 10cm, 40cm, and 60cm marks, the 10 and the40 are on one side of the pivot, and the 60 is on the other side, 10 cmfrom the pivot. It's all starting to come together.On one side:-- There is a weight at the "10cm" mark. That point is 40 cm from the pivot,and the weight is 100N, so the moment pulling this side down is 4,000 N-cm.-- There is another weight at the "40cm" mark, and that's 10cm from the pivot.The weight is 150N, giving us another 1,500 N-cm pulloing this side down.-- The total moment pulling this side down is (4,000 + 1,500) = 5,500 N-cm.-- (Plus another 25 x 100 = 5,000 due to the weight of 1/2 the stick. But theother half is already balancing that much, so I don't think we need to worryabout the weight of the stick at all. This is typical of these meter sticks thatare manufactured by the Red Herring Pedagogical Industries Group LLC ofEckveldt, South Dakota, and so often used in these Physics demonstrations.)-- At the "60cm" mark, 10cm from the pivot on the other side, is hanging aweight of 300N. That gives us 3,000 N-cm of moment working against the twoweights on the first side.-- In order to balance the whole thing, we have to provide only another(5,500 - 3,000) = 2,500 N-cm on the second side.-- All we can say is: The product of (the weight of a single weight hung fromthe second side) multiplied by (its distance in centimeters from the pivot) mustbe 2,500.-- The lightest weight that can do the job is 50N, if it's hung at the endofthe stick on the second side, 50cm from the pivot. If we have more weight toplay with, then it can be hung closer to the pivot, just as long as (weight) times (distance from the pivot) = 2,500 N-cm.


A nylon guitar string vibrates in a 90 cm standing wave pattern what is the wavelength of the wave?

For the pattern shown in Fig. 5.1, the length of the sring is equal to 3 half-wavelengths: L = 3(λ/2). So the wavelength (of the travelling waves giving the pattern) is: λ =2/3rd L =2/3rd(0.90 m) = 0.60 m L = 60 cm The answer is 60cm.


If you tried to nonchalantly smuggle gold bricks by filling your backpack whose dimensions are 60cm X 25cm X 15cmwhat would its mass be please show the solution?

We know that the density of gold = m/v the volume is given in cm, so you have to convert each value into meters so you have .6m X .25m X .15m the density of gold is 19.3 x103 KG mass = density X volume mass = 19.3 x 103(.6 x .25 x .15) mass = 434.25 kg


What are the uses of linear expansion apparatus?

Measure the coefficients of different metal expansion.This Linear Expansion testing device makes studying the expansion of metals simple and instantly visible to the student. A metal rod is inserted into the steam chamber and steam is applied. Expansion of the rod is immediately registered by the dial indicator that is mounted on one end. The heat jacket has three inlet tubes for water intake, outlet and thermometer insertion. Unit includes four metal rods 6mm x 60cm of aluminum, steel, copper, and brass. A steam source is not provided. The unit measures 8 cm x 10 cm x 70cm. Instructions included.ref: physics lab