In AC service, it's written that way because 1-volt x 1-Amp is generally not 1-watt.
The problem arises because inductive or capacitive loads on the line have the effect
of introducing a 'phase angle' ... the phenomenon where the AC voltage and current
don't both wiggle at exactly the same time.
"Watts" measure the useful power drawn from the line, power that can heat a
toaster or turn a strong motor. If the voltage and current don't exactly line up,
then the amount of useful power is reduced. In the extreme, if voltage and
current are offset by 90 degrees of the cycle, then the line delivers no useful
power at all.
The amount by which the voltage and current on the line are separated in time
is called the "power factor". It's just the cosine of the phase angle between
voltage and current, and it's always equal to '1' or less.
The "watts" of real, useful power delivered on the line is (voltage) x (current) x (power factor).
So the kilowatts of real power is equal to (KVA) x (power factor).
We have no way of knowing what the power factor is on the line that the question
is referring to.
Since most of the household load consists of inductive devices ... things with
coils in them, like motors and toasters ... the power factor can be improved by
hanging capacitors across the line to compensate. Look carefully up the utility
poles in your neighborhood while you're walking (not driving), and eventually
you'll spot a group of rectangular cans mounted on the pole, probably near a
transformer. Those are the line capacitors that compensate for the inductive
load, increase the power factor, and help squeeze more watts out of every KVA.
1 MW = 10 to the power 6 Watts (in the new wiki answers type face).
A ton of refrigeration is equal to the cooling power of one short ton (2000 pounds or 907 kilograms) of ice melting in a 24-hour period. The value is defined as 12,000 BTU per hour, or 3517 watts. A 2-ton ac represents 7034 watts of power, but a practical unit would require more electrical power than that, maybe 10 kW to be safe.
1 megawatt is equivalent to 1000 kilowatts. the measure of Watt is power fed to purely resistive loads. KVA is a measure of power, regardless of whether the load is resistive or reactive. For direct conversion from KVA to KW or vice versa, a power factor is needed.
10 joules per second = 10 watts
There are 3.75 kW in 3750 watts. To convert watts to kilowatts, you divide by 1000.
Yes, 2.8 kVA is equal to 2800 watts. This is because 1 kVA is equivalent to 1000 watts, so 2.8 kVA would be 2800 watts.
8,000 watts = 8 kVA / (the power factor) If the power factor is 1, then 8 kVa = 8,000 watts.
2.5 kVA is equal to 2500 watts.
0 - 1000. KVA times a power factor gives you kilowatts, 1000 x watts. If the power factor is 0, then o watts make up your one kVA; if the power factor is 1, then 1000 watts make up your one kVA. Typical power factor is in the range of .8 to 1.
There are ~5.9 kVA with 5600 watts and a power factor of 0.95. power factor is defined as the real power (watts) divided by the complex power (volt amperes): .95 = 5600/VA VA = 5600/.95 = 5894.7VA = 5.89kVA
It could be as much as 63 kW (63,000 Watts) into a load with a power factor of 1.0. For other loads, multiply the kVA by the power factor.
There are 1,000 watts (W) in a kilowatt (kW) and 1,000 volt-amps (VA) in a kilovolt-ampere (kVA). Therefore, 1 kVA is equal to 1 kW.
Formulas you need for single phase calculations. KVA = I x E/1000, KW = I x E x pf (where pf = power factor). For your question multiply the KVA by the power factor to get KW and then move the decimal point three places to the right to get watts. They are virtually the same. A watt is volts times amps. KVA is thousand of volts time amps. KVA and KW ratings are the same.
1hp = 735.5 watts 16,000 kVA / 735.5 = 21.754 hp
To determine how many 120-volt, 7-amp lights can be run on a 15 kVA transformer, first convert the transformer capacity to watts: 15 kVA equals 15,000 watts. Each light draws 120 volts * 7 amps = 840 watts. Dividing the transformer capacity by the wattage of each light gives 15,000 watts / 840 watts per light ≈ 17.86. Therefore, you can run a maximum of 17 lights on a 15 kVA transformer.
1 kVA (kilovolt-ampere) is equal to 1,000 VA (volt-ampere). The relationship between VA and watts depends on the power factor of the electrical system. For a system with a power factor of 1 (perfectly efficient), 1 kVA is equal to 1 kW (kilowatt). However, for systems with lower power factors, the relationship between kVA and kW will vary.
There are a few components missing from your question. I need to know either the voltage or the amperage and the power factor. For single phase, the formula for Kilowatts is Amps x Volts x pf/1000. The formula for Kilovolt-Amperes is Amps x Volts/1000. As you can see more info is needed.