To calculate the cost of using a 40-watt power device per hour, you need to know the cost of electricity per kilowatt-hour (kWh) from your utility company. You can then convert the watts to kilowatts (40 watts is 0.04 kW) and multiply that by the number of hours used to find the kWh consumed. Finally, multiply the kWh consumed by the cost per kWh to determine the total cost.
-- The voltage makes no difference. -- The 400W device dissipates ten times as much power as the 40W device does. We don't know how much of each one's power consumption is radiated in the form of heat, UV light, etc. But if the spectral distribution of their output is similar, then the one that dissipates more power produces more visible light, and appears brighter.
40W on a light bulb indicates that the bulb consumes 40 watts of power. This measurement refers to the amount of energy the bulb consumes to produce light. In general, higher wattage bulbs produce more light but also consume more energy.
The first thing you have to do is find out how much you are being charged per kWh from the utility company. 40 watts is .040 kW. If the bulb was left on for an hour.040 kWh times what you are charged from the utility company and you will have your answer. Now that you have read a simple answer, lets add reality. A 40W T-8/T-10/T-12 fluorescent bulb requires a specialized fixture for it to function. As part of that fixture a starter and ballast are included that also must be powered at nominal 80% efficiency and add cost to the user. The next factor that must be considered has to do with environmental costs. each method of illumination does so via creation of heat. The heat must be dissipated and offset. The nominal temperature at the exciter of a 40W fluorescent tube is 110 degrees F with 70 degree F ambient environment. The nominal temperature of a fast start ballast (starter included) is 130 degrees F in the same ambient environment. This stated, the cost to run a single 40W fluorescent tube one hour will be the sum of the 40W consumed by the bulb plus the cost to run the fixture plus the cost to offset the additional heat produced. Therefore expect to use your cost per KWh times .048 plus environmental cost. Remember that even in incandescent lighting the environmental factors also play.
75W means bulb which give 75W power when connected to domestic light. Power is nothing but energy per second. Thus energy consumed by bulb can be calculated as follows. E = 75*60*60*4J = 1080kJ
To convert power in watts to decibels (dB), you can use the formula: dB = 10 * log10(P2/P1), where P1 is the reference power (usually 1 watt) and P2 is the power you are converting (40 watts in this case). Plugging in the values, you would calculate: dB = 10 * log10(40/1) = 16.02 dB.
The average home fluorescent lamp consumes 40W of power. Running for one hour it will consume 0.04 KWh. Units of electricity are charged per Kilowatt hour.
It's the 40W tube! because it's nonlinear: indeed it generates harmonics which increase the apparent power and thus the apparent energy.
A 40W fluorescent lamp typically draws around 0.33 amperes in a 120V circuit. This is calculated by dividing the power (40W) by the voltage (120V) to get the amperage.
To calculate the kilowatt-hour consumption, you first need to convert the wattage to kilowatts by dividing it by 1000 (40W = 0.04 kW). Then multiply the power in kilowatts by the time in hours (0.04 kW * 1750 h = 70 kWh). Therefore, the 40W lamp will consume 70 kilowatt-hours if it remains on for 1750 hours.
The energy consumption of the 40W lamp can be calculated as follows: Energy consumption = Power (kW) x Time (hours) Energy consumption = 40 W / 1000 (to convert W to kW) x 1750 hours = 70 kWhThe kilowatt-hour consumption of a 40W lamp if it remains on for 1750 hours is 70 kWh (kilowatt-hours).
-- The voltage makes no difference. -- The 400W device dissipates ten times as much power as the 40W device does. We don't know how much of each one's power consumption is radiated in the form of heat, UV light, etc. But if the spectral distribution of their output is similar, then the one that dissipates more power produces more visible light, and appears brighter.
Voltage x Current = Power So Power / voltage = current Now you do the math
were is the place were 12 06s and 78 40w
The 100W bulb emits more light energy per second than the 40W bulb, so it appears brighter due to the higher intensity of light. This increase in brightness is a result of the higher power consumption and light output of the 100W bulb compared to the 40W bulb.
You probably worded your question wrong, since the answer would be 40w. But I'll work out the charge to run it for you. I am working your questions using the MELBOURNE, AUSTRALIA power tariff (charge) which is 17.000c per kw/h. It takes roughly 25 hours for your 40w fluoro tube to consume 1 kilowatt of power, so the power consumption per hour would be around 0.0068 cents an hour. Please take note of other amounts of electricity that have to be used in order to fire up your tube though, as some starter capacitors can use a big amount of energy (this is the reason why it is not recommended to use fluoro bulbs on 12v/24v - 240v/110v inverters). So basically, if you are going to be out of the room for less than 1 hour, leave it on.
40W on a light bulb indicates that the bulb consumes 40 watts of power. This measurement refers to the amount of energy the bulb consumes to produce light. In general, higher wattage bulbs produce more light but also consume more energy.
Treating this as an ideal resistance, voltage will be half, so current will be half. Power (which is V * I) is one fourth, so you will only draw 10W.