Not sure what you mean. 50 J = 50 J.
q=6C V=3V U=qV=(6C)(3V)=18 J U(potential energy)=18 Joules (18J)
The potential energy of the skater at 12 meters above the ground can be calculated using the formula: Potential energy = mass * acceleration due to gravity * height. Given that the mass is 60 kg, acceleration due to gravity is 9.81 m/s^2, and the height is 12 meters, the potential energy would be approximately 7,058.4 Joules.
If the turbine were perfectly efficient, all of the potential energy of 19600 joules would be converted into mechanical energy. To convert this to power output in watts, you would divide the energy by the time taken for the conversion to occur. If the conversion happened in 10 seconds, the power output would be 1960 watts (19600 joules / 10 seconds).
The potential energy of the 3-kg vase can be calculated using the formula: potential energy = mass * gravity * height. With a mass of 3 kg, gravity as 9.81 m/s^2, and a height of 2.5 meters, the potential energy would be approximately 73.58 Joules.
The potential energy of the crate is given by the formula: Potential energy = mass * gravity * height. Plugging in the values, we get: PE = 50kg * 9.8 m/s^2 * 10m = 4900 Joules. So, the crate has 4900 Joules of potential energy after being lifted.
Well, 40 percent of 250 I guess! Which, if you are not good at arithmetic is 100 Joules.
From what I understand: PE - Potential Energy (mgh) KE - Kinetic Energy (1/2 mv2) If one dismisses the friction with air (conservation of energy), a loss of 7 joules for potential energy means a gain of 7 Joules in kinetic energy.
q=6C V=3V U=qV=(6C)(3V)=18 J U(potential energy)=18 Joules (18J)
The potential energy of the skater at 12 meters above the ground can be calculated using the formula: Potential energy = mass * acceleration due to gravity * height. Given that the mass is 60 kg, acceleration due to gravity is 9.81 m/s^2, and the height is 12 meters, the potential energy would be approximately 7,058.4 Joules.
If the turbine were perfectly efficient, all of the potential energy of 19600 joules would be converted into mechanical energy. To convert this to power output in watts, you would divide the energy by the time taken for the conversion to occur. If the conversion happened in 10 seconds, the power output would be 1960 watts (19600 joules / 10 seconds).
100. The amount of energy a roller coaster has is maintained throughout the whole journey. Its the conservation of energy - energy can' t be created or destroyed it can only be transferred. It therefore depends what type of energy you mean in the question. It can have a total of 100 joules meaning yes, anywhere on the roller coaster it will remain as 100 joules however if your saying 100 joules of gravitational potential energy at the top by the bottom of the hill it will have decreased and have been converted into at least 80 joules of kinetic energy leaving 20 joules as gravitational potential energy. Sorry for the poor grammar; just focus on the science. I have an exam on this in two weeks...
The potential energy of the 3-kg vase can be calculated using the formula: potential energy = mass * gravity * height. With a mass of 3 kg, gravity as 9.81 m/s^2, and a height of 2.5 meters, the potential energy would be approximately 73.58 Joules.
The potential energy of the crate is given by the formula: Potential energy = mass * gravity * height. Plugging in the values, we get: PE = 50kg * 9.8 m/s^2 * 10m = 4900 Joules. So, the crate has 4900 Joules of potential energy after being lifted.
Joules, all energy is measured in joules.
The potential energy of the vase can be calculated using the formula: Potential Energy = mass * acceleration due to gravity * height. Plugging in the values: Potential Energy = 3 kg * 9.8 m/s^2 * 2.5 m = 73.5 Joules.
Voltage cannot be directly converted from joules, as they are different units of measurement. Joules represent energy, while voltage is a measure of electric potential difference. To determine voltage, you would need more information such as current and resistance in the circuit.
0.144 JOULES. One can calculate this from the formula E=Vq in which E is energy, V is potential difference & q is charge.