36.8 kj
The specific heat capacity of lead is 0.128 J/g°C. To calculate the heat energy required to melt the lead, you would first need to raise the temperature of the lead from 24°C to its melting point of 327.5°C using the equation Q = mcΔT. Then, once the lead is at its melting point, you would calculate the heat energy required to melt the lead using the equation Q = mL, where L is the heat of fusion for lead which is 23.5 kJ/kg.
The energy required to melt 1 kg of copper at its melting point of about 1084°C is approximately 205 kJ. Therefore, to melt 2 kg of copper, you would need around 410 kJ of energy.
To melt 2 kg of gold, it would require approximately 66,190 Joules per gram. Therefore, for 2 kg of gold, the total energy required would be around 132,380,000 Joules.
The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.
The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.
36.8 kj
The measurement of how much heat energy is required for a substance to melt is called the heat of fusion. It is the amount of energy required to change a substance from a solid to a liquid at its melting point.
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
The specific heat capacity of lead is 0.128 J/g°C. To calculate the heat energy required to melt the lead, you would first need to raise the temperature of the lead from 24°C to its melting point of 327.5°C using the equation Q = mcΔT. Then, once the lead is at its melting point, you would calculate the heat energy required to melt the lead using the equation Q = mL, where L is the heat of fusion for lead which is 23.5 kJ/kg.
The energy required to melt 1 kg of copper at its melting point of about 1084°C is approximately 205 kJ. Therefore, to melt 2 kg of copper, you would need around 410 kJ of energy.
The energy required to melt a substance can be calculated using the formula: Energy = mass x heat of fusion. For water, the heat of fusion is 334 J/g. Therefore, the energy required to melt 56g of water would be 56g x 334 J/g = 18,704 J.
J mesons are subatomic particles that do not experience a melting phase transition like larger particles or materials. As such, they do not require energy to melt as they do not solidify.
To melt 2 kg of gold, it would require approximately 66,190 Joules per gram. Therefore, for 2 kg of gold, the total energy required would be around 132,380,000 Joules.
The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.
The heat of fusion for gold is 64.4 kJ/mol. To convert this to energy required to melt 1.5 kg of gold, we need to calculate the number of moles in 1.5 kg of gold (1.5 kg of gold is approximately 0.047 moles). Then, the energy required would be approximately 3.03 kJ.
The specific heat of gold is 0.129 J/g°C, and its melting point is 1064°C. The energy required to melt 1.5 kg of gold can be calculated using the formula: Energy = mass * specific heat * temperature change. So, the energy required would be approximately 2.3 x 10^6 Joules.
414 kJ