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How much energy is required to raise the temperature of 0.2kg of aluminum for 15 degrees celsius to 18 degrees celsius?
The specific heat capacity of aluminum is 0.9 J/g°C. To calculate the energy required to raise the temperature of 0.2kg of aluminum by 3 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. Substituting the values into the formula, Energy = 0.2kg x 0.9 J/g°C x 3°C = 0.54 Joules.
How much energy is required to raise the temperature of 0.2 kg of aluminum from 15 degrees celsius to 18 degrees celsius?
The specific heat capacity of aluminum is 900 J/kg°C. The change in temperature is 3°C. Using the formula Q = mcΔT, the energy required would be 0.2 kg * 900 J/kg°C * 3°C = 540 J. So, the energy required to raise the temperature is 540 Joules.
How much energy is required to raise the temperature of 3kg of aluminum from 18 degrees Celsius to 23 degrees Celsius?
The specific heat capacity of aluminum is 0.902 J/g°C. First, convert 3kg to grams (3000g). Then, calculate the change in temperature (23°C - 18°C = 5°C). Finally, use the formula Q = mcΔT to find the energy required: Q = 3000g * 0.902 J/g°C * 5°C.
How much heat energy is needed to raise the temperature of a 055kg sample of aluminum from 22.4 degrees celsius to 94.6 degrees celsius?
The heat energy required can be calculated using the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the aluminum (0.055 kg), c is the specific heat capacity of aluminum (900 J/kg°C), and ΔT is the change in temperature (94.6°C - 22.4°C = 72.2°C). Plugging in the values, we get Q = 0.055 kg * 900 J/kg°C * 72.2°C = 3582.7 J. Hence, 3582.7 Joules of heat energy is needed to raise the temperature of the aluminum sample.
How much energy is required to raise the temperature of 3 kg of aluminum from 18 degrees C to 23 degrees C?
The specific heat capacity of aluminum is 0.897 J/g°C. First we need to convert the mass to grams: 3 kg = 3000 g. Then we can use the formula: energy = mass x specific heat x change in temperature. Plugging in the values: energy = 3000 g x 0.897 J/g°C x (23°C - 18°C) = 13,485 J. So, 13,485 Joules of energy is required.
How much energy is required to raise the temperature of 0.2kg of aluminum for 15 degrees celsius to 18 degrees celsius?
The specific heat capacity of aluminum is 0.9 J/g°C. To calculate the energy required to raise the temperature of 0.2kg of aluminum by 3 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. Substituting the values into the formula, Energy = 0.2kg x 0.9 J/g°C x 3°C = 0.54 Joules.
How much energy is required to raise the temperature of 0.2 kg of aluminum from 15 degrees celsius to 18 degrees celsius?
The specific heat capacity of aluminum is 900 J/kg°C. The change in temperature is 3°C. Using the formula Q = mcΔT, the energy required would be 0.2 kg * 900 J/kg°C * 3°C = 540 J. So, the energy required to raise the temperature is 540 Joules.
Which would take more energy to increase temperature by 5 degrees water or Aluminum?
It would take more energy to increase the temperature of water by 5 degrees than aluminum. This is because water has a higher specific heat capacity, meaning it requires more energy to raise its temperature compared to aluminum.
How much energy is required to raise the temperature of 3kg of aluminum from 18 degrees Celsius to 23 degrees Celsius?
The specific heat capacity of aluminum is 0.902 J/g°C. First, convert 3kg to grams (3000g). Then, calculate the change in temperature (23°C - 18°C = 5°C). Finally, use the formula Q = mcΔT to find the energy required: Q = 3000g * 0.902 J/g°C * 5°C.
How much heat energy is needed to raise the temperature of a 055kg sample of aluminum from 22.4 degrees celsius to 94.6 degrees celsius?
The heat energy required can be calculated using the formula: Q = mcΔT, where Q is the heat energy, m is the mass of the aluminum (0.055 kg), c is the specific heat capacity of aluminum (900 J/kg°C), and ΔT is the change in temperature (94.6°C - 22.4°C = 72.2°C). Plugging in the values, we get Q = 0.055 kg * 900 J/kg°C * 72.2°C = 3582.7 J. Hence, 3582.7 Joules of heat energy is needed to raise the temperature of the aluminum sample.
What term describes the amount of thermal energy that is required to raise the temperature of a substance by 1.0 degrees Celsius?
Specific heat capacity is the term that describes the amount of thermal energy required to raise the temperature of a substance by 1.0 degree Celsius.
What energy unit is defined as the heat required to raise one kilogram of water by one degrees celsius?
I believe it is Calorie.
How much energy is required to raise the temperature of 3 kg of aluminum from 18 degrees C to 23 degrees C?
The specific heat capacity of aluminum is 0.897 J/g°C. First we need to convert the mass to grams: 3 kg = 3000 g. Then we can use the formula: energy = mass x specific heat x change in temperature. Plugging in the values: energy = 3000 g x 0.897 J/g°C x (23°C - 18°C) = 13,485 J. So, 13,485 Joules of energy is required.
How many kilowatts are required to raise the temperature of 1000 liters of water by 10 degrees centigrade?
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
How much energy is required to raise the temperature of 0.2 kg of aluminum from 15 degrees C to 18 degrees C?
The specific heat capacity of aluminum is 0.902 J/g°C. First we convert the mass from kg to grams (0.2 kg = 200 g). Then we calculate the energy using the formula: Q = mcΔT, where Q is the energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, we get Q = 200g * 0.902 J/g°C * (18 - 15)°C. Solving this gives us the energy required to be approximately 541 J.
How much energy is needed to raise the maximum temperature of 10kg of water from 20 degrees Celsius to 80 degrees Celsius?
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
