The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, you get: Energy = 3000g x 0.45 J/g°C x 5°C = 6750 Joules.
The specific heat capacity of iron is 0.45 J/g°C. To raise the temperature of 3kg (3000g) of iron by 5 degrees Celsius, you would need: 3000g x 0.45 J/g°C x 5°C = 6750 Joules of energy.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required to raise the temperature of 2 kg of iron by 3 degrees Celsius, you can use the formula: Energy = mass x specific heat capacity x temperature change. Plug in the values to find the answer.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
The specific heat capacity of iron is 0.45 J/g°C. Therefore, the energy required to raise the temperature of 3 kg (3000 g) of iron by 3°C is calculated as follows: Energy = mass x specific heat capacity x temperature change. Plugging in the values, we get Energy = 3000g x 0.45 J/g°C x 3°C = 4050 Joules.
To calculate the energy released to raise the temperature of 2kg of iron from 20 to 23 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of iron is approximately 0.45 J/g°C. First, convert 2kg to 2000g. Then calculate the energy released using these values.
The specific heat capacity of iron is 0.45 J/g°C. To raise the temperature of 3kg (3000g) of iron by 5 degrees Celsius, you would need: 3000g x 0.45 J/g°C x 5°C = 6750 Joules of energy.
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required to raise the temperature of 2 kg of iron by 3 degrees Celsius, you can use the formula: Energy = mass x specific heat capacity x temperature change. Plug in the values to find the answer.
538J
The specific heat capacity of iron is 0.45 J/g°C. To calculate the energy required, you can use the formula: Energy = mass x specific heat capacity x change in temperature. Plugging in the values, Energy = 5g x 0.45 J/g°C x (30°C - (-10°C)). This calculation would give you the energy in joules required to raise the temperature of 5 grams of iron from -10ºC to 30ºC.
The formula is: 0,108 x 3000 x (T1 -T2), in kilocalories.
The specific heat capacity of iron is 0.45 J/g°C. Therefore, the energy required to raise the temperature of 3 kg (3000 g) of iron by 3°C is calculated as follows: Energy = mass x specific heat capacity x temperature change. Plugging in the values, we get Energy = 3000g x 0.45 J/g°C x 3°C = 4050 Joules.
The change in temperature is 25 degrees Celsius, meaning it takes 22.48 joules per degree of change. The specific heat of iron is 0.449 J/g degree Celsius. This means that the mass of iron must be 50.07 grams
To calculate the energy released to raise the temperature of 2kg of iron from 20 to 23 degrees Celsius, you would use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of iron is approximately 0.45 J/g°C. First, convert 2kg to 2000g. Then calculate the energy released using these values.
The specific heat capacity of iron is 0.45 J/g°C. To find the energy required to raise the temperature of 2kg of iron from 20°C to 23°C, you would use the formula: Energy = mass x specific heat capacity x change in temperature. So, Energy = 2,000g x 0.45 J/g°C x (23°C - 20°C). Calculate this to find the energy required.
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
1935 J
To raise the temperature of both an equal amount, water would require more energy. In terms of the energy required to raise the temperature: iron = 0.45 joules / gram . kelvin water = 4.2 joules / gram . kelvin This is known as the specific heat capacity of a material