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How much energy must be transfered by heat to the engines surroundings if 2.5 kj is transfered by heat to the engine with 8.5 percent efficciency?
Wiki User
∙ 12y ago
There are two possible answers to this question - depending on how you read it:
If 2.5 kJ is converted to work but that only represents 8.5% efficiency, then the heat transferred to the surroundings will be 2.5(1-0.85)/0.85 = 26.9 kJ
On the other hand, if 2.5 kJ is the total energy coming in and only 8.5% of it is converted to work, then the other 91.5% is lost to the surroundings:
2.5(1-0.085) = 2.2875 kJ
Wiki User
∙ 12y ago
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