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How much energy is required to vaporize 2 kg of gold Use the table below and this equation?
The heat of vaporization of gold is 158 kJ/kg. To find the total energy required to vaporize 2 kg of gold, you can use the equation: Energy = mass * heat of vaporization. Substitute the values to get: Energy = 2 kg * 158 kJ/kg = 316 kJ. Therefore, 316 kJ of energy is required to vaporize 2 kg of gold.
How much of the energy contained originally in the grass is usable by the lion?
Roughly 10% of the energy contained in the grass is available for the lion to use. This is due to energy transfer inefficiencies as you move up the food chain, with most of the energy being lost as heat during metabolic processes.
How much energy is produced when the sun converts 10 kg of mass into energy?
The energy produced by converting 10 kg of mass into energy is calculated using Einstein's famous equation E=mc^2. For 10 kg of mass, the energy produced would be approximately 9 x 10^17 joules.
How much joules of energy is present in 1 kg of water?
The amount of energy present in 1 kg of water is typically around 4,186,000 joules at room temperature. This value represents the energy required to raise the temperature of 1 kg of water by 1 degree Celsius.
How much energy is required to vaporize 1.5 kg of copper?
1650kj
How much energy is required to vaporize 2 kg if aluminum?
To calculate the energy required to vaporize 2 kg of aluminum, we use the heat of vaporization of aluminum, which is approximately 10,900 J/kg. Therefore, the energy required is 2 kg × 10,900 J/kg = 21,800 J, or 21.8 kJ. This is the amount of energy needed to convert 2 kg of aluminum from a liquid to a vapor at its boiling point.
How much energy does an airplane engine produce?
The energy does a airplane engine produce is 10 kg of ht?
How much is a kilogram in length?
kg is an abbreviation for kilograms, a measurement of mass or weight. If you meant kilometer, then it is 1,000 meters or 0.6 miles approximately.
How much energy is required to vaporize 2 kg of gold Use the table below and this equation?
The heat of vaporization of gold is 158 kJ/kg. To find the total energy required to vaporize 2 kg of gold, you can use the equation: Energy = mass * heat of vaporization. Substitute the values to get: Energy = 2 kg * 158 kJ/kg = 316 kJ. Therefore, 316 kJ of energy is required to vaporize 2 kg of gold.
How much energy is needed to vaporize 2 kg of aluminum?
To vaporize aluminum, you need to consider its heat of vaporization, which is approximately 10,700 kJ/kg. For 2 kg of aluminum, the total energy required would be 2 kg × 10,700 kJ/kg, equating to about 21,400 kJ. Therefore, around 21.4 million joules of energy is needed to vaporize 2 kg of aluminum.
How much of energy contained originally in the grass is usable by the lion?
0.1 kg
How much energy is required to vaporized 1.5 kg of copper?
7095 kJ
How much energy is required to vaporize 1.5 kg of aluminum (refer to table of latent heat values.)?
To calculate the energy required to vaporize 1.5 kg of aluminum, we need to use the latent heat of vaporization for aluminum, which is approximately 10,900 J/kg. The energy required can be calculated using the formula: Energy = mass × latent heat of vaporization. Thus, for 1.5 kg of aluminum: Energy = 1.5 kg × 10,900 J/kg = 16,350 J. Therefore, 16,350 joules of energy is required to vaporize 1.5 kg of aluminum.
How much of the energy contained originally in the grass is usable by the lion?
Roughly 10% of the energy contained in the grass is available for the lion to use. This is due to energy transfer inefficiencies as you move up the food chain, with most of the energy being lost as heat during metabolic processes.
How much energy is produced when the sun converts 10 kg of mass into energy?
The energy produced by converting 10 kg of mass into energy is calculated using Einstein's famous equation E=mc^2. For 10 kg of mass, the energy produced would be approximately 9 x 10^17 joules.
How much energy do you need to cook an egg?
You need 40 Pounds or 20 KG to cook an egg because if you have 20 KG When you have 5 Kg hand power.
How much joules of energy is present in 1 kg of water?
The amount of energy present in 1 kg of water is typically around 4,186,000 joules at room temperature. This value represents the energy required to raise the temperature of 1 kg of water by 1 degree Celsius.
