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How many kilowatts are required to raise the temperature of 1000 liters of water by 10 degrees centigrade?

Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.


How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?

The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.


How much joules does it take to heat water to 100 degrees?

To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.


What would happen to liquid water if energy is removed?

If energy is removed from liquid water, it would cool down and eventually freeze into solid ice at its freezing point (0 degrees Celsius or 32 degrees Fahrenheit).


How much energy will it take to raise 7.3 kg of water from 10 degrees Celsius to 90 degrees celsius?

To find the energy required to raise the temperature of water, you can use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of water is 4.18 J/g°C. Therefore, the energy required to raise 7.3 kg of water from 10°C to 90°C would be 7.3 kg x 4.18 J/g°C x (90°C - 10°C).

Related Questions

How many kilowatts are required to raise the temperature of 1000 liters of water by 10 degrees centigrade?

Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.


How much energy would you use to raise temperature of kg of water by 2 degrees Celsius?

The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.


How many btus does it take to raise half pound of water 1 degree?

One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.


How long would it take to heat 200 gallons of water 180 degrees if the water was 50 degrees and you only had 600 Btu water heater?

To calculate the time it would take to heat 200 gallons of water by 180 degrees using a 600 Btu water heater, you would first determine the total heat required: Calculate the heat energy required: Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the temperature change. Then, calculate the time required to heat the water using the formula: Time = Q / power of the heater. These calculations will give you an estimate of the time needed to heat the water based on the specific heat capacity of water and the power of the heater.


How much joules does it take to heat water to 100 degrees?

To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.


How much energy is needed to raise the maximum temperature of 10kg of water from 20 degrees Celsius to 80 degrees Celsius?

The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.


How many calories are required to raise the temperature of 1 g of water by 5 degrees C?

1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.


What would happen to liquid water if energy is removed?

If energy is removed from liquid water, it would cool down and eventually freeze into solid ice at its freezing point (0 degrees Celsius or 32 degrees Fahrenheit).


How much energy will it take to raise 7.3 kg of water from 10 degrees Celsius to 90 degrees celsius?

To find the energy required to raise the temperature of water, you can use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of water is 4.18 J/g°C. Therefore, the energy required to raise 7.3 kg of water from 10°C to 90°C would be 7.3 kg x 4.18 J/g°C x (90°C - 10°C).


Which would burn the most 100g of water at 100 degrees or 100g of steam at 100 degrees?

Burning 100g of water at 100 degrees would release more energy than burning 100g of steam at 100 degrees, as water at a higher temperature has more thermal energy to be released. Burning water at 100 degrees would first need to raise its temperature to its boiling point before converting it into steam.


Which would take more energy to increase temperature by 5 degrees water or Aluminum?

It would take more energy to increase the temperature of water by 5 degrees than aluminum. This is because water has a higher specific heat capacity, meaning it requires more energy to raise its temperature compared to aluminum.


How much energy would be required to change 24.7 g of ice to liquid water?

The energy required to change ice to liquid water is known as the heat of fusion. For ice to water, the heat of fusion is 334 J/g. Therefore, to change 24.7 g of ice to liquid water, the energy required would be 24.7 g * 334 J/g = 8259.8 J.