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Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
If energy is removed from liquid water, it would cool down and eventually freeze into solid ice at its freezing point (0 degrees Celsius or 32 degrees Fahrenheit).
To find the energy required to raise the temperature of water, you can use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of water is 4.18 J/g°C. Therefore, the energy required to raise 7.3 kg of water from 10°C to 90°C would be 7.3 kg x 4.18 J/g°C x (90°C - 10°C).
Kilowatts is a unit of energy rate, while the temperature required to raise a specific volume of water by a specific amount of degrees is a unit of energy, not energy rate. The question cannot, therefore, be answered as stated. Please restate the question.
The amount of energy required to raise the temperature of 1 kg of water by 1 degree Celsius is approximately 4,186 Joules. Therefore, to raise the temperature by 2 degrees Celsius, you would need about 8,372 Joules of energy.
One BTU is the energy required to raise one pound of water by one degrees. Therefore, your answer would be one half.
To calculate the time it would take to heat 200 gallons of water by 180 degrees using a 600 Btu water heater, you would first determine the total heat required: Calculate the heat energy required: Q = mcΔT, where Q is the heat energy, m is the mass of water, c is the specific heat of water, and ΔT is the temperature change. Then, calculate the time required to heat the water using the formula: Time = Q / power of the heater. These calculations will give you an estimate of the time needed to heat the water based on the specific heat capacity of water and the power of the heater.
To heat 1 gram of water by 1 degree Celsius, it takes 4.18 joules. So, to heat water from, for example, 20 degrees to 100 degrees, you would need to calculate the total mass of water and apply the specific heat capacity to determine the total energy required.
The energy required to raise the temperature 1 degree Celsius of 1 gram of water (1 mL) is 1 calorie (=4.18 J). So for 1 kg, 1Kcal (= 4180 J = 4.18 KJ) is required. To raise it 60 degrees, just multiply by 60 and for 10 kg multiply by 10 again. That would make 2.508 MJ (= 2508000 J) Now this is not completely accurate. The energy required to raise the temperature of water differs at 20 degrees from that at 60 degrees. The difference is small (~0.05 J or something like that) but still present.
1 calorie is the energy required to raise 1 gram of water by 1 degree C. So it would take 5 calories to raise it by 5 degrees C.
If energy is removed from liquid water, it would cool down and eventually freeze into solid ice at its freezing point (0 degrees Celsius or 32 degrees Fahrenheit).
To find the energy required to raise the temperature of water, you can use the formula: Energy = mass x specific heat capacity x temperature change. The specific heat capacity of water is 4.18 J/g°C. Therefore, the energy required to raise 7.3 kg of water from 10°C to 90°C would be 7.3 kg x 4.18 J/g°C x (90°C - 10°C).
Burning 100g of water at 100 degrees would release more energy than burning 100g of steam at 100 degrees, as water at a higher temperature has more thermal energy to be released. Burning water at 100 degrees would first need to raise its temperature to its boiling point before converting it into steam.
It would take more energy to increase the temperature of water by 5 degrees than aluminum. This is because water has a higher specific heat capacity, meaning it requires more energy to raise its temperature compared to aluminum.
The energy required to change ice to liquid water is known as the heat of fusion. For ice to water, the heat of fusion is 334 J/g. Therefore, to change 24.7 g of ice to liquid water, the energy required would be 24.7 g * 334 J/g = 8259.8 J.