To counteract a force of 20 N, you need another force, also of 20 N, in the opposite direction.
The force needed to keep a 20N stone from falling would need to be 20N or greater in the opposite direction to counteract the force of gravity pulling the stone downwards. This force would need to be applied vertically upwards to effectively balance the gravitational force acting on the stone.
The horizontal force can be calculated using the formula Fhorizontal = Fcos(θ), where F is the given force (20N) and θ is the angle of inclination (30 degrees). Plugging in the values, we get Fhorizontal = 20N x cos(30) ≈ 17.3N.
The net force is the difference between the two forces. In this case, the net force is 20N (left force) - 10N (right force) = 10N to the left.
The work done by Amy is given by the formula Work = Force x Distance. Thus, the work done by Amy can be calculated as 20N x 10m = 200 Joules.
The net force produced is 10N, which is the difference between the two forces (30N - 20N). The direction of the net force would be in the direction of the larger force (30N).
The force needed to keep a 20N stone from falling would need to be 20N or greater in the opposite direction to counteract the force of gravity pulling the stone downwards. This force would need to be applied vertically upwards to effectively balance the gravitational force acting on the stone.
The force of friction is equal and opposite to the applied force in this scenario, so the force of friction on the object would also be 20N. This allows the object to remain in a state of equilibrium and not accelerate.
Probably not, however the speed of the collision is important. You can generally push something with one hand to a force of about 100N so 20N isn't that much but might hurt at high speed. Maybe. A 20N force could be stopping a 1kg mass moving at only 1m/s, in 0.05 seconds. If you stop it with your head, I'm pretty sure it would hurt. If you stop it with your fleshy butt (no offense), it would take longer to stop, and the force would be less than 20N.
Work = (force) x (distance) = (20n) x (2m) = 40 newton-meters = 40 joules.
The horizontal force can be calculated using the formula Fhorizontal = Fcos(θ), where F is the given force (20N) and θ is the angle of inclination (30 degrees). Plugging in the values, we get Fhorizontal = 20N x cos(30) ≈ 17.3N.
The net force is the difference between the two forces. In this case, the net force is 20N (left force) - 10N (right force) = 10N to the left.
No force is needed to keep an object moving. An object with no forces on it keeps moving at a constant speed in a straight line. If there is any force acting on it to make it slow down, then you need just enough force to cancel the first one, in order to keep it moving.
The work done by Amy is given by the formula Work = Force x Distance. Thus, the work done by Amy can be calculated as 20N x 10m = 200 Joules.
The net force produced is 10N, which is the difference between the two forces (30N - 20N). The direction of the net force would be in the direction of the larger force (30N).
10
To determine the force needed to move the object, you can use the work-energy principle - work done is equal to the force applied multiplied by the distance moved. Given that the work is 160J and the distance is 8m, the force required can be calculated as 160J / 8m = 20N. Therefore, a force of 20N would be needed to move the object 8m across the floor.
40 J