it depends how cold the ice is
The heat required to melt ice at its melting point is known as the heat of fusion, which is 334 J/g. Therefore, the heat needed to melt 68.5 g of ice is 68.5 g x 334 J/g = 22,939 J.
No, the amount of heat required to boil 1kg of water is much higher than the amount of heat required to melt 1kg of ice. Boiling water requires additional heat to overcome the latent heat of vaporization, while melting ice only requires heat to overcome the latent heat of fusion.
The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.
It would take approximately 334,000 Joules of heat to melt a 1 kg block of ice at 0 degrees Celsius. This energy is required to break the bonds holding the ice molecules together and transition from a solid to a liquid state, known as the heat of fusion.
The heat required to melt ice is called the heat of fusion, which is 334 J/g. To melt 500g of ice, you would need 334 J/g x 500g = 167000 joules of heat.
The heat required to melt ice at its melting point is known as the heat of fusion, which is 334 J/g. Therefore, the heat needed to melt 68.5 g of ice is 68.5 g x 334 J/g = 22,939 J.
The energy required to melt ice is known as the heat of fusion, which is about 334 joules per gram. Therefore, it would take approximately 3340 joules of energy to melt 10g of ice.
No, the amount of heat required to boil 1kg of water is much higher than the amount of heat required to melt 1kg of ice. Boiling water requires additional heat to overcome the latent heat of vaporization, while melting ice only requires heat to overcome the latent heat of fusion.
The amount of energy required to melt ice can be calculated using the equation: energy = mass of ice * heat of fusion. The heat of fusion for ice is 334 J/g, so for 32.0 g of ice, the energy required would be 32.0 g * 334 J/g = 10,688 J.
how many calories are required to melt a 1.52g ice cube?
This heat is 32,48 joules.
The heat required to vaporize 500 grams of ice at its freezing point is the sum of the heat required to raise the temperature of the ice to its melting point, the heat of fusion to melt the ice, the heat required to raise the temperature of water to its boiling point, and finally the heat of vaporization to vaporize the water. The specific heat capacity of ice, heat of fusion of ice, specific heat capacity of water, and heat of vaporization of water are all needed to perform the calculations.
Heat required to melt 1 g of ice at 0°C is approximately 80 cal . This is also called latent heat of fusion of ice.
It would take approximately 334,000 Joules of heat to melt a 1 kg block of ice at 0 degrees Celsius. This energy is required to break the bonds holding the ice molecules together and transition from a solid to a liquid state, known as the heat of fusion.
The heat of fusion of water, which is the amount of heat energy required to melt one gram of ice at its melting point, is approximately 334 joules per gram. This means that to melt an ice cube, the ice must absorb 334 joules of heat energy per gram to transition from a solid to a liquid state.
The heat required to melt ice is called the heat of fusion, which is 334 J/g. To melt 500g of ice, you would need 334 J/g x 500g = 167000 joules of heat.
The specific heat capacity of ice is 2.09 J/g°C and the heat of fusion of ice is 334 J/g. To melt 2 kg of ice, you first need to heat the ice from -30°C to 0°C, then provide energy to melt the ice at 0°C. The total energy required is 9836 J + 66800 J = 76636 J.